Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Hello there, multiply to each side of ratio until you get the answer, which in this case you have to multiply 4 to each side, therefore...
B= 28
A= 16.
Hope this helps!!
~Brainliest
1. Make y the subject of the equation
y = -4 - 6x
2. Substitute values for guess and check
8 = -4 - (6 x 2)
8 = -4 - 12
This is incorrect.
2 = -4 - (6 x 1)
2 = -4 -6
This is incorrect.
-10 = -4 - (6 x 1)
-10 = -4 -6
This is correct.
The correct answer is C.
We know that Bob and Caitlyn are playing a trading-card game. Between them, they have 81 cards. <span>Bob has 7 fewer cards than Caitlyn. Since Bob has 7 cards fewer them Caitlyn we have to divide by 2 and subtract 7.
81 / 2 = 40 [rounded]
40 - 7 = cards Bob has
= 33 cards bob has
</span>
Answer: There are approximately 853827 new cases in 6 years.
Step-by-step explanation:
Since we have given that
Initial population = 570000
Rate at which population decreases is given by
Now,
First year =570000
Second year is given by
Third year is given by
so, there is common ratio ,
it becomes geometric progression, as there is exponential decline.
so,
a=570000
common ratio is given by
number of terms = 6
Sum of terms will be given by
We'll put this value in this formula,
So, there are approximately 853827 new cases in 6 years.
