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3 years ago

There is a ratio of 5 girls to 3 boys in the chour there are 24 boys in the chours how many girls are in the chours

Mathematics

1 answer:

Misha Larkins [42]3 years ago

3 0

Answer:

I believe it would be 40

Step-by-step explanation:

5:3 = x:24

3 times 8 = 24

5 times 8 = 40

There are 40 girls in the chorus.

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Boston has an area of 90 square miles. It has a population density of 6862 people per square mile. What is the population of Bos

Tamiku [17]

Divide 315,530,612 by 3,539,225 to get 89 people per square mile (rounded)

3 0

3 years ago

Which expression is equivalent to 18x2 – 50?

kondor19780726 [428]

Answer:

(3) 2(3x - 5)(3x + 5)

Step-by-step explanation:

$18 {x}^{2} - 50 \\ = 2(9 {x}^{2} - 25) \\ = 2(3x - 5)(3x + 5)$

6 0

4 years ago

To subtract 78 - 35 mentally Carmen out of 5 to each number and Karen a tattoo to each number will both met at work to find the

Vinil7 [7]

215 is the answer because 78-35 =43 43×5=215

4 0

4 years ago

Two lines interesting at a right angle

schepotkina [342]

Answer:

Perpendicular lines are lines that intersect at right angles.

Step-by-step explanation:

I'm assuming that your question is asking what the term is for two lines that intersect at a right angle. If I'm correct then your answer is perpendicular lines.

Hope this helps

7 0

3 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

4 years ago