<u>ANSWER: </u>
The roots of
are 
<u>SOLUTION:</u>
Given, quadratic equation is
--- eqn (1)
We need to find the roots of given quadratic equation using quadratic formula.
Quadratic formula for general quadratic equation
is 
Here, for eqn (1) a = 6, b= -9 and c = 2



Hence the roots of
are 
Answer:
x = 114
Step-by-step explanation:
since the triangles are congruent then corresponding angles are congruent, then
∠ C = ∠ D , that is
x + 18 = 132 ( subtract 18 from both sides )
x = 114
Answer:
4×^2-4×-3=0factor(2×+1)
(2×-3)=0 2×+1=0 2+-3=0 2×=-1
2×=3 ×=-1/2 ×=3/2
×=1/2, 3/2
The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.
Step-by-step explanation:
The given is,
Given diagram is combination of Rectangle and Semi circle.
Step:1
Res the attachment,
Area of given diagram = Area of A + Area of B..............(1)
Step:2
For A,
The A section in the given diagram is semi circle,
Diameter of semi circle = Total distance - ( 2+3)
( ∵ 2, 3 are top distance in the given diagram)

Diameter, d = 5 cm
Radius, 

r = 2.5 cm
Area,
........................(2)


Step:3
For B,
Area of rectangle is,
.....................(3)
Where, l - Length = 10 cm
b - Width = 2 cm
Equation (3) become,


Area of B,
= 20 
Step:4
From the equation (1),
Area of given diagram = 20+ 9.81747
Area = 29.817 square centimeters
Result:
The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.
(9 * 2) + 1 = 18 + 1 = 19/2 is it's fractional notation/mixed number.