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Crank
2 years ago
7

Web design people please help!

Computers and Technology
1 answer:
Rainbow [258]2 years ago
6 0

I think the answer is number 3!

I hope this helps!

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350 square feet requires 1 gallon of paint. Assign gallons_paint with the amount of paint required for wall_area. Sample output
Marina CMI [18]
Here's a solution in node.js. Can be easily transcribed to other languages:

var paint_per_sqf = 1/350;
var wall_area = 250.0;
var gallons_paint = wall_area * paint_per_sqf;

console.log(wall_area.toFixed(1) + " square feet wall will need:");
console.log(gallons_paint.toFixed(12) + " gallons of paint");


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The master system database stores a database template that is used as a blueprint when creating a new user database.
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<span>An attribute in a relation of a database that serves as the primary key of another relation in the same database is called a</span>
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Mandarinka [93]
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7 0
3 years ago
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The U.S. consumes lots of energy. Which fuel provides the most energy?
Nadya [2.5K]

Answer:

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Explanation:

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2 years ago
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WILL GIVE BRAINIEST! Your users are young children learning their arithmetic facts. The program will give them a choice of pract
Ierofanga [76]

In python:

numA = [4, 1, 6, 10, 2, 3, 7, 9, 11, 12, 5, 8]

numB = [2, 12, 10, 11, 1, 3, 7, 9, 4, 8, 5, 6]

while True:

   i = 0

   userChoice = input("Adding or Multiplying? (a/m) ")

   if userChoice == "a":

       while i < len(numA):

           answer = int(input("What is {} + {} ".format(numA[i],numB[i])))

           if answer == numA[i] + numB[i]:

               print("Correct!")

           else:

               print("That's incorrect. The right answer is {}".format(numA[i] + numB[i]))

           i += 1

   elif userChoice == "m":

       while i < len(numA):

           answer = int(input("What is {} * {} ".format(numA[i], numB[i])))

           if answer == numA[i] * numB[i]:

               print("Correct!")

           else:

               print("that's incorrect. The right answer is {}".format(numA[i] * numB[i]))

           i += 1

4 0
3 years ago
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