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alisha [4.7K]
3 years ago
15

Ses

Computers and Technology
1 answer:
jekas [21]3 years ago
8 0

Answer:

Amoung us

Explanation:

When the imposter is sus

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Inaccurate __________ is the number-one reason why many small businesses go bankrupt.
givi [52]

Answer:

Option B

Explanation:

The top most reason for the bankruptcy of many small businesses is the inaccurate credit management.

Credit management deals with granting credits, recovery of credit granted on its due time,  terms of grant of credits, other related issues and to make sure it comply with the company's policies.

The main aim of credit management is to work for the improvement of profits generated and the revenues within a bank or a firm.

Therefore, any inaccuracy in these will result in major set back to many small businesses.

4 0
3 years ago
Which of the following regarding the Ames test is true? a. It is used to identify newly formed auxotrophic mutants. b. It is use
alexandr1967 [171]

Answer:

A

Explanation:

5 0
3 years ago
he is trying to find information on the internet first he navigated to a search engine entered the keywords database administrat
Vlada [557]

Answer:

b

Explanation:

b

6 0
3 years ago
1. Implement the function dict_intersect, which takes two dictionaries as parameters d1 and d2, and returns a new dictionary whi
stich3 [128]

Answer:

1  

def dict_intersect(d1,d2): #create dictionary

  d3={} #dictionaries

  for key1,value1 in d1.items():       #iterate through the loop  

      if key1 in d2:   #checking condition

          d3[key1]=(d1[key1],d2[key1])   #add the items into the dictionary  

  return d 3

print(dict_intersect({'a': 'apple', 'b': 'banana'}, {'b': 'bee', 'c': 'cat'})) #display

2

def consolidate(*l1):  #create consolidate

  d3={} # create dictionary

  for k in l1:       #iterate through the loop

      for number in k:   #iterate through  the loop                               d3[number]=d3.get(number,0)+1   #increment the value

             return d 3 #return

print(consolidate([1,2,3], [1,1,1], [2,4], [1])) #display

Explanation:

1

Following are  the description of program

  • Create a dictionary i.e"dict_intersect(d1,d2) "   in this dictionary created a dictionary d3 .
  • After that iterated the loop and check the condition .
  • If the condition is true then add the items into the dictionary and return the dictionary d3 .
  • Finally print them that are specified in the given question .

2

Following are  the description of program

  • Create a dictionary  consolidate inside that created a dictionary "d3" .
  • After that iterated the loop outer as well as inner loop and increment the value of items .
  • Return the d3 dictionary and print the dictionary as specified in the given question .

5 0
4 years ago
Def build_dictionary(string):
MissTica

Answer:

Follows are the code to this question:

def build_word_counter(string):#defining a method build_word_counter that accepts string as a parameter  

   d = dict()#defining d variable as a dictionary

   for x in string:#defining for loop that use string

       x = x.lower()#Use lower method  

       if not d.get(x):#defining if block that holds value in d variable

           d[x] = 1#use dictionary to hold value in 1

       else:#defining else block

           d[x] += 1#use dictionary to increment value by 1

   return d#return dictionary

print(build_word_counter(["Like","like","LIKE"]))#use print method to call method

def build_letter_distribution(string):#defining a method build_letter_distribution that accepts string variable

   d = dict()#defining d variable as a dictionary

   for i in string:#defining for loop to count string value

       for j in i:#defining for loop to hold string as number

           if not d.get(j):#defining if block that doesn't get value in dictionary  

               d[j] = 1#hold value in dictionary  

           else:#defining else block

               d[j] += 1#use dictionary to increment the dictionary value

   return d#return dictionary

print(build_letter_distribution(["Like","test","abcdEFG"]))#use print method to return its value

Output:

please find the attached file.

Explanation:

In the first program a method, "build_word_counter" is defined that accepts a string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the for loop to hold string value and convert all value into lower case.

In the next step, a conditional statement is used that holds value in the dictionary and count its word value.

In the second program a method, "build_letter_distribution" is defined that holds string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the two for loop and in if the block, it holds value in the dictionary and returns its value, and use print method to print its return its value.

4 0
3 years ago
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