I have a feeling I've seen this question before
anyway
A=number of hours that plan A is
B=number of hours that plan B is
so
on wednesday, 7hr
5A and 6B so
5A+6B=7
on thursday, 3 hours
3 of A and 2 of B
3A+2B=3
so we gots
5A+6B=7
3A+2B=3
elimination
eliminate B's
multiply 2nd equation by -3 and add to 1st equation
5A+6B=7
<u>-9A-6B=-9 +</u>
-4A+0B=-2
-4A=-2
divide both sides by -4
A=1/2
A=0.5
sub back
3A+2B=3
3(0.5)+2B=3
1.5+2B=3
minus 1.5 both sides
2B=1.5
divide by 2 both sides
B=0.75
plan A lasts 1/2 hour or 0.5 hour or 30 mins
plan B lasts 3/4 hour or 0.75 hour or 45 mins
Answer:
y = 
(x - 5)² - 2
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (5, - 2), thus
y = a(x - 5)² - 2
To find a substitute (7, 0) into the equation
0 = a(7 - 5)² - 2
0 = 4a - 2 ( add 2 to both sides )
2 = 4a ( divide both sides by 4 )
a = 
=
y = (x - 5)² - 2 ← in vertex form
Answer:The area of a circle with diameter 3.5 is 7
Step-by-step explanation:
Answer:
Step-by-step explanation:
27 is the "center" of a range of measurements of the height of the guard rail. The height could be as much as 30 inches or as little as 24 inches. The absolute value operator encloses "x - 27," where 27 is the "center." The acceptable excess or acceptable deficiency is 3 inches.
So now we can eliminate possible answers B and C, in both cases because 27 is inappropriately greater than 3.
Narrowing down our choices, we have h + 27 and h - 27 inside the absolute value operator. 27 is a positive quantity (height of the guard rail), so the inequality showing +27 as the "center" is correct; that is
D: |h - 27| ≤ 3 (measurements in inches).
Answer:
(x-4) (x-3) (x+3)
Step-by-step explanation:
x^3 - 4x^2 - 9x + 36
Make 2 groups
x^3 - 4x^2 - 9x + 36
We can factor out x^2 from the first group and -9 from the second group
x^2 (x-4) - 9(x-4)
Now factor out (x-4)
(x-4) (x^2 -9)
This may be an answer choice but we can still factor
(x^2 -9) is the difference of squares
(x^2-9) = (x-3) (x+3)
Replacing this
(x-4) (x-3) (x+3)
