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Temka [501]
2 years ago
7

PLEASSSE HELP MEEE

Mathematics
1 answer:
Ainat [17]2 years ago
4 0

Answer:

  cot(theta) = 1/(-3/8)

Step-by-step explanation:

cot(theta) = 1/tan(theta) = 1/(-3/8)

_____

<em>Comment on the answer</em>

The parentheses are required. With them, the value is cot(theta) = -8/3. Without them, the value is cot(theta) = -1/24, which is not correct.

Even if the answer is typeset, it must be done in such a way as to make it clear what the numerator and denominator are:

\displaystyle\frac{1}{-\frac{3}{8}}

You might be interested in
Which statements are true for the following expression?<br> (9 + 1) · 5
kvasek [131]

Answer:

50

Step-by-step explanation:

add

9 + 1 = 10

multiply

10 * 5 = 50

Answer: 50

3 0
2 years ago
A rectangle has a perimeter of 54 cm. It has a length of 15 cm. What is its area? *
d1i1m1o1n [39]

the area is 180 cm. to find the perimeter you would do 15+15+14+14 to get 54 cm. So for area you do (l×w) which is 15×14=180.

5 0
2 years ago
Anybody good at math?
Lerok [7]
Yup! We're all pretty good here. :)
8 0
3 years ago
What is 9 5/6 - 2 1/3
Mariana [72]
9 5/6 - 2 1/3 is 7 1/2.

You could get this answer by finding the same denominator of the fractions. The LCM of both is 6. Multiply the 1 of the second fraction 2 times because you had to multiply the denominator 2 times to get to 6. 
You should have 2 2/6.

Now get 9 5/6 - 2 2/6.

The answer is 7 3/6, simplifies into 7 1/2.
9 5/6 - 2 1/3 is 7 1/2.


5 0
3 years ago
Read 2 more answers
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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