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Ber [7]
3 years ago
9

Based on the similar triangles shown below, Theodore claims that ∆TUV is transformed to ∆WXY with a scale factor of 32. Is Theod

ore correct? A Yes, the triangles are similar with a scale factor of 32. B No, the triangles are similar with a scale factor of 21. C No, the triangles are similar with a scale factor of 23. D No, the triangles are similar with a scale factor of 43.

Mathematics
1 answer:
Anarel [89]3 years ago
8 0

*Correct Question:

Based on the similar triangles shown below, Theodore claims that ∆TUV is transformed to ∆WXY with a scale factor of 3/2. Is Theodore correct?

A. Yes, the triangles are similar with a scale factor of 3/2.

B. No, the triangles are similar with a scale factor of 2/1.

C. No, the triangles are similar with a scale factor of 2/3.

D. No, the triangles are similar with a scale factor of 4/3.

Answer:

C. No, the triangles are similar with a scale factor of 2/3.

Step-by-step explanation:

∆TUV is the original triangle. After transformation, the size reduced to give us ∆WXY. This means ∆TUV was reduced by a scale factor to give ∆WXY. The scale factor should be a fraction, suggesting, the original size of the ∆ was reduced upon transformation.

Thus, the ratio of their corresponding sides = the scale factor.

This is: \frac{8}{12} = \frac{16}{24} = \frac{12}{18} = \frac{2}{3}

If you multiply the side length of ∆TUV by ⅔, you'd get side length of ∆WXY.

So, Theodore is wrong.

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Mrs Kennedy is buying pencils for 315 students.

The pencils are sold in boxes of 10.

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so we have to round off 315 to the nearest ten, that's 320.

so then she has to buy 320 pencils

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Please help!<br> And explain the answers too!
RideAnS [48]
1) He worked 4 hours leaving 6 more hours for him.
rate for A alone 6 baker
rate for A & B together 4
1/a+1/b=1/x
1/6+1/b=1/4
1/b=1/4-1/6
1/b=6/24-4/24
1/b=2/24
1/b=1/12
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12/72+6/72=1/4
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But we want to know how long it would have taken her for the whole job not just part of it
he works twice as fast as she does so the job that takes him 10 hours alone would take her 20 hours alone.

2) jessica and cynthia work in a pet shop.
it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them.
if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish?
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let t = time it takes them to finish (C's working time)
then
t+1 = J's working time
let 1 = completed job (all pets groomed)
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A shared work equation, each does a fraction of the job, the two fractions add up to 1
%28%28t%2B1%29%29%2F6 + t%2F8 = 1
Multiply by the least common multiple of 6 and 8, 24. cancel the denominators
4(t+1) + 3t = 24
4t + 4 + 3t = 24
4t + 3t = 24 - 4
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3) math club takes 40 minutes
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quantity = 1 set up of the tables.
rate for math club is 1/40 of all the tables in 1 minute.
rate for science club is 1/50 of all the tables in 1 minute.
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rate * time = quantity
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rate * time = quantity
the rates of the math club and the science club are additive.
(1/40 + 1/50) * time = 3/4 of the tables that still need to be set up.
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how to check.
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Step-by-step explanation:

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