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ASHA 777 [7]
3 years ago
11

Somebody please help me on this?! What is the correct postulate or theorem for this one..

Mathematics
1 answer:
IRINA_888 [86]3 years ago
7 0

Answer:

Segment Addition Postulate

Step-by-step explanation:

In geometry, the Segment Addition Postulate states that given 2 points A and C(in this case S and O), a third point B(in this case R) lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Meaning for R to lie on the line SO;

SR + RO must be equal to SO

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What is the sum of 1 1/2 and 4 2/3
Eddi Din [679]
Hi,

Work:

1 \frac{1}{2} + 4 \frac{2}{3} \\ \\ 1 \frac{3}{6} + 4 \frac{4}{6} = 5 \frac{7}{6} = 6 \frac{1}{6}

Hope this helps.
r3t40
6 0
3 years ago
Read 2 more answers
What is the following quotient
Likurg_2 [28]

Answer:

Rationalize the denominator by multiplying by the conjugate of (1 + √3), namely (1 - √3). this gives us

(1 - √3) / (1 - 3) or (1 - √3) / -2, which can be rewritten as

(-1 + √3)/2, the last answer choice.

7 0
3 years ago
Point B, located at (-4,-7), is reflected over the y-axis. What are the coordinates of B?
hram777 [196]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
The weights of the chocolate in Hershey Kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.10
dusya [7]

The distribution is not a standard normal distribution.

We know that the variable (X) usually obeys and follows a standard normal distribution provided that the summation of (X) is zero and the variance of the random variable V(X) = 1.

Mathematically:

E(X) = 0 and V(X) = 1

Given that;

  • the mean which follows a normal distribution (X) = 4.5338 g, and
  • the standard deviation SD(X) = 0.1039 g

As such, the distribution is not a standard normal distribution.

Therefore, we can conclude that the distribution is not a standard normal distribution.

Learn more about standard normal distribution here:

brainly.com/question/11876263?referrer=searchResults

7 0
3 years ago
A population is normally distributed with mean 18 and standard deviation 1.7. (a) Find the intervals representing one, two, and
elena55 [62]

Answer:

Interval within 1 standard deviation: (16.3,19.7)

Interval within 2 standard deviation: (14.6, 21.4)

Interval within 3 standard deviation: (12.9, 23.1)

Step-by-step explanation:

We are given the following in the question:

Population mean, \mu = 18

Standard deviation, \sigma = 1.7

We have to find the following intervals:

Interval within 1 standard deviation:

\mu \pm 1\sigma\\=18 \pm 1.7\\=(16.3, 19.7)

Interval within 2 standard deviation:

\mu \pm 2\sigma\\=18 \pm 2(1.7)\\= 18 \pm 3.4\\=(14.6,21.4)

Interval within 3 standard deviation:

\mu \pm 3\sigma\\=18 \pm 2(1.7)\\= 18 \pm 5.1\\=(12.9,23.1)

6 0
4 years ago
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