the denominator cannot be zero, because the division by zero is not defined, therefore:
![\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2-9%3D0%20%5C%5C%20%5Ctext%7BSolving%20for%20x%3A%7D%20%5C%5C%20x%5E2%3D9%20%5C%5C%20%5Csqrt%5B%5D%7Bx%5E2%7D%3D%5Csqrt%5B%5D%7B9%7D%20%5C%5C%20x%3D%5Cpm3%20%5Cend%7Bgathered%7D)
Therefore the domain of (f o g)(x) is:
Answer:
12 is thy number lol
Step-by-step explanation:
1/2x + 3 = 5 - 2/3x
Subtract the 1/2x
You get 3 = 5 - 1/6x
Subtract the five.
-2 = -1/6x
Multiply by -6
x = 12
283
Start by doing multiplication and division from left to right to follow the order of operations.
270 + 12 / 3 + 9
270 + 4 + 9
Now do addition and subtraction from left to right.
274 + 9
283
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With what do you need help with
Answer:x=7& y= 2
Step-by-step explanation:
x+3y=13
3x+2y=25
Using elimination method
We have
3× x+3y=13......I
1×3x+2y=25....ii
3x+9y=39
3x+2y=25
7y=14
Divide through by 7
y=2
Substitute for y in equation i
x+3(2)=13
x+6=13
x=7
