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3 years ago

Find sin(C). round to the nearest hundredth if necessary.

Mathematics

2 answers:

natka813 [3]3 years ago

6 0

For this case we have to define trigonometric relations of rectangular triangles that the sine of an angle is given by the leg opposite the angle on the hypotenuse of the triangle. That is to say:

$Sin (C) = \frac {5} {13}\\Sin (C) = 0.38$

Answer:

Option A

Basile [38]3 years ago

5 0

Answer:

A) 0.38

Step-by-step explanation:

By SOH CAH TOA, the sine of an angle is its opposite side divided by the hypotenuse.

The opposite of ∠C is 5, and the hypotenuse is 13.

So, sin(C) = 5/13 ≈ 0.38.

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90% of a number is x . What is 100% of the number? Assume x>0

mariarad [96]

Step-by-step explanation:

Let the required number be n

$\therefore \: \frac{90}{100} \times n = x \\ \\ \therefore \: \frac{9}{10} \\ \\ \therefore \:n = \frac{10}{9} x \\ \\ \therefore 100\% \: of\:n = \frac{10}{9} x \times 100\% \\ \\ = \frac{10}{9} x \times \frac{100}{100} \\ \\ = \frac{10}{9} x \\$

NOTE: A number is always 100% in itself.

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3 years ago

Bethany sells roses and petunias. The expression 3r+2.5p gives the cost (in dollars) of r roses and pp petunias. What is the cos

a_sh-v [17]

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3 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.