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4 years ago

If you were to have two mixed numbers that both add up to 4, which two mixed numbers would it be?

Mathematics

1 answer:

Jobisdone [24]4 years ago

7 0

Answer:

multiple answers

Step-by-step explanation:

2 3/4 + 1 1/4

1 3/4 + 3 1/4

and so on

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dmitriy555 [2]

Answer:

+ + + + += + + + + +

Step-by-step explanation:

DUH

I mean I think I'm right

8 0

3 years ago

Convert the following number to a percent 68/ 23 If needed, round to the nearest whole.

zepelin [54]

Step-by-step explanation:

$\frac{68}{23}$

$= 2.956521739130434$

$= 2.956521739130434 \times 100$

= 295.6521739130434%

=296%

5 0

2 years ago

Read 2 more answers

On a road trip, you drive about 70 miles per hour and your friend drives about 60 miles per hour. The plan is to drive less than

lord [1]

Answer: The answer is 0 hours and 10 hours.

Step-by-step explanation: Given that me and my friend are on a road trip. My speed is 70 miles per hour and my friend's speed is 60 miles per hour. Our plan is to drive less than 15 hours and at least 600 miles each day.

Also, my friend will drive more hours than me.

Let, 'x' and 'y' be the number of hours drove by me and my friend respectively. Then, according to the given information, we have the following inequalities.

$y>x,\\\\x+y$

When we plot these inequalities in a graph paper, we can see in the attached figure, where the common shaded region gives the solution set, one of the solution is point 'P', given by

x = 0 and y = 10.

This solution satisfy all the three conditions given above.

Thus, one of the solution is - I will drive for 0 hours and my friend will drive for 10 hours.

8 0

3 years ago

F(x, y, z) = z tan−1(y2)i + z3 ln(x2 + 3)j + zk. find the flux of f across s, the part of the paraboloid x2 + y2 + z = 18 that l

Cerrena [4.2K]

$\mathbf F(x,y,z)=z\tan^{-1}(y^2)\,\mathbf i+z^3\ln(x^2+3)\,\mathbf j+z\,\mathbf k$
$\implies\mathrm{div}\mathbf F(x,y,z)=0+0+1=1$

By the divergence theorem, the flux of $\mathbf F$ across the *closed* surface $\mathcal S$ combined with the plane $z=2$ is given by a volume integral over the closed region:

$\displaystyle\iint_{\mathcal S}\mathbf F\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}\nabla\cdot\mathbf F\,\mathrm dV$

So in fact, to find the flux over $\mathcal S$ alone, we'll need to subtract the flux of $\mathbf F$ over the planar portion, oriented outward. First, compute the volume integral by converting to cylindrical coordinates:

$x^2+y^2+z=18$
$z=2\implies x^2+y^2=16\implies r^2=16\implies r=4$

$\displaystyle\iiint_{\mathcal R}\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}\int_{z=2}^{z=18-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=128\pi$

If the surface does actually contain $z=2$ , then you can stop here; otherwise, continue.

Now, parameterize the part of the *closed* surface in $z=2$ by

$\mathbf s(r,\theta)=r\cos\theta\,\mathbf i+r\sin\theta\,\mathbf j+2\,\mathbf k$

where $0\le r\le4$ and $0\le\theta\le2\pi$ . We get a surface element

$\mathrm d\mathbf S=(\mathbf s_r\times\mathbf s_\theta)\,\mathrm dr\,\mathrm d\theta=(r\,\mathbf k)\,\mathrm dr\,\mathrm d\theta$

We don't need to worry about the first two components of

and so the surface integral over this region is

$\displaystyle\iint_{z=2\,\land\,x^2+y^2\le16}\mathbf F\cdot\mathrm d\mathbf S=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}2r\,\mathrm dr\,\mathrm d\theta=32\pi$

Then the total flux over $\mathcal S$ alone is $(128-32)\pi=96\pi$ .

4 0

3 years ago

Pls help this is factoring... 100 points

Natali [406]

Answer:

here's how you can factor it:)

Step-by-step explanation:

$x^{2}$ =6x+9

=(x+3)(x+3)

x= -3

8 0

3 years ago

Read 2 more answers