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TEA [102]
3 years ago
14

Write 2^100 as an exponent with a base of: 32

Mathematics
1 answer:
jeka943 years ago
8 0

Answer:

32^20

Step-by-step explanation:

Here you can either:

Convert to logarthmic format and use base changing formula.

OR

Simply do 2^100=32^x, find x.

I chose option 2 because its quicker here. However, it will not always work.






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Hannah and Dawson have both invested money in savings accounts with APYs of 3.2%. If Hannah's account has a balance of $31,000 a
9966 [12]

Answer:

$341.07

Step-by-step explanation:

Hanna and Dawson both invested at 3.2% = 0.032

Hannah has balance of 31,000 in account

Dawson has balance of 42000 in account

Interests earned by both are

1)Hannah -P(1+i)^-n

=31000(1+0.032)^-1

=31000(1.032)^-1

=31000(0.968992)

=$30038.752

=$30038.75

Interest earned by Dawson is $31,000 - $30038.75 = $961.25

2)Dawson-  P(1+i)^-n

=42000(1+0.032)^-1

=42000(1.032)^-1

=42000(0.968992)

=$40697.664

=$$40697.664

Interest earned by Dawson is $42,000 - $40697.66= $1302.32

3) Hence the amount that Dawson earns than is:

=$1302.32-$961.25

= $341.07

3 0
3 years ago
Rajans school is having a raffle. The school sold raffle tickets with 3-digits. Each digit is either 1,2,or 3. The school also s
belka [17]

Answer:

Step-by-step explanation:

We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.

Therefore we have the following raffle tickets:

123

132

213

231

312

321

000

000

From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.

Probability of 123 to be picked=

1/8 => 0.125

Probability of 000 to be picked=

2/8 => 0.25

Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked

8 0
2 years ago
M
viva [34]

Answer:

0

Step-by-step explanation:

4 0
3 years ago
What is the answer to 3 times 1 plz write correct answer
il63 [147K]

Answer:

3

Step-by-step explanation:

the answer to 3 times 1 is 3

7 0
2 years ago
A student records the repair cost for 22 randomly selected dryers. A sample mean of $98.78 and standard deviation of $15.49 are
Gelneren [198K]

Answer:

The critical value that should be used is T = 2.0796.

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 22 - 1 = 21

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0796, which is the critical value that should be used.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0796\frac{15.49}{\sqrt{22}} = 6.868

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912

The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

8 0
3 years ago
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