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3 years ago

7

Solve. x^2 8x 25 = 0

1 answer:

kykrilka [37]3 years ago

6 0

This equation is unsolvable.
x^2+8x+16=0
(x+4)^2+9=0
(x+4)^2= -9
anything to the power of whatever has to be greater than -1, it means it can be 0 or more but never a negative number. If it is a negative number, then it is false.

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Given: M(-4,-1), B(-5,-3) find the midpoint

Dmitry [639]

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\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
M&({{ -4}}\quad ,&{{ -1}})\quad 
% (c,d)
B&({{ -5}}\quad ,&{{ -3}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
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jolli1 [7]

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Step-by-step explanation:

20=$5.49

1=20/5.49

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kherson [118]

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Which expressions are equivalent to the one below? Check all that apply.<br><br>log 2 - log 6

Marina CMI [18]

Answer:

Given the expression: log 2 -log 6

Use the logarithmic rule :

$\log(\frac{m}{n}) = \log m - \log n$

$\log x^n = n\log x$

Use the above rule to solve the expression:

$\log 2 -\log 6 = \log \frac{2}{6} = \log \frac{1}{3}$ [∴ $\log(\frac{m}{n}) = \log m - \log n$ ]

or

$\log 2 -\log 6 =\log 2+ \log 6^{-1} = \log 2 + \log \frac{1}{6}$ [∴ $\log x^n = n\log x$ ]

or

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Answer:

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Step-by-step explanation:

-6x^2-7x+3≤0

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