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TiliK225 [7]
3 years ago
15

Add. Find the expression in standard form. (15y − 9 + 6y^2) + (10 − 5y) = _________

Mathematics
1 answer:
elena55 [62]3 years ago
4 0
Wasnt sure if you were asking just for the standard form of that equation 
<span>(15y − 9 + 6y^2) + (10 − 5y) = 0 ) or if you wanted the equation simplified and then in standard form ( 6y^2 + 10y + 1 = 6 ) so i did both </span>
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The question is in the picture above. Please help
kow [346]

Answer:

it is 1

Step-by-step explanation:

5 0
3 years ago
Find the measure of the missing angles.
sukhopar [10]

Answer:

B= 133°  C= 47°

Step-by-step explanation:

As shows on the right it's 133°

A= 133°

c+a =180° -a

= 180° -133°

=47°

a and c complement each other and

b= a = 133°

a and b are vertical angles

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HELP ASAP 100 POINTS!!!
nikklg [1K]
<h3>Answer:  choice 4. f(x) and g(x) have a common x-intercept</h3>

===========================================================

Explanation:

For me, it helps to graph everything on the same xy coordinate system. Start with the given graph and plot the points shown in the table. You'll get what you see in the diagram below.

The blue point C in that diagram is on the red parabola. This point is the x intercept as this is where both graphs cross the x axis. Therefore, they have a common x intercept.

------------

Side notes:

  • Choice 1 is not true due to choice 4 being true. We have f(x) = g(x) when x = 2, which is why f(x) > g(x) is not true for all x.
  • Choice 2 is not true. Point B is not on the parabola.
  • Choice 3 is not true. There is only one known intersection point between f(x) and g(x), and that is at the x intercept mentioned above. Of course there may be more intersections, but we don't have enough info to determine this.

7 0
3 years ago
Read 2 more answers
The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

7 0
3 years ago
Use the properities to find the sum or product of 93+[68+7]
kondor19780726 [428]

Answer:

the answer for this questionis 93(68+7)

8 0
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