The direct variation equation is y =kx
Lets see:-
4y/4 = x/4
y = 1/4x
<span>Answer: Yes, this is a direct variation </span>
Answer:
C) Izzy
Step-by-step explanation:
Justin typed 90 words in 2 minute:
work
405/9=45 words a minute
45*2=90
Remmy typed 84 words in 2 minute:
work
420/10=42 words a minute
42*2=84
Izzy typed 98 words in 2 minutes:
work
588/12= 49 words a minute
49*2 = 98
I hope this helps :)
Alright, let's do this! If $25 is one fifth of how much the game system cost then, multiply 25 times 5. And you should get your answer.
I hope this helps.
Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
Answer: 5*2*2*3*3
Step-by-step explanation:
First you divide 180 by 2 and you get 90. Then you proceed to divide that by 2 again and get 45. You will then divide 45 by 3 to get 15. Then divide 15 by 3 again and get 5, which cannot be divided any smaller.
180/2=90
90/2=45
45/3=15
15/3=5
