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3 years ago

How do I do this. I don't know how to do it.

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

4 0

Answer:

I'm guessing, say all of them are 20 cm, by the looks of it

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11. Use an inequality symbol (<, >, 2, =) to compare -26

svetlana [45]

Answer:

c. <

Step-by-step explanation:

-26 < (less than) 54

8 0

3 years ago

30 people watched the soccer game last night tickets cost 2.75 each half of these fans bought a program at 1.50 each how much mo

Dima020 [189]

Answer: 105$
Half the ppl paid 1.50 for programs which is 15 x 1.5 = 22.5
30 ppl bought tickets 30x2.75
Add the totals to get 105

5 0

3 years ago

- 2/3x + 5(3/5 - 3/5x) - 12 divided 6 *2

Ira Lisetskai [31]

Answer: -3 2/3x - 1

Step-by-step explanation:

-2/3x + 5(3/5 - 3/5x) - 12 / 6 * 2

First distribute

-2/3x + 3 - 3x - 12 / 6 * 2

Now divide 12 by 6

-2/3x + 3 - 3x -2 * 2

Now multiply -2 by 2

-2/3x + 3 - 3x - 4

Now subtract 3x from -2/3x

-3 2/3x + 3 - 4

Now subtract 4 from 3

-3 2/3x - 1

4 0

3 years ago

Pls helppp<br> math work<br> bleh

joja [24]

Answer:

q = -2

Step-by-step explanation:

when solving 12q >= -24 you get

q >= -2 (12 divides 24 by 2)

therefore q is greater or equal to -2.

3 0

3 years ago

What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

3 years ago

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How do I do this. I don't know how to do it. ​

How do I do this. I don't know how to do it.