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melamori03 [73]
3 years ago
12

What is the value of the expression below? (7^1/2)^2

Mathematics
2 answers:
4vir4ik [10]3 years ago
5 0

Answer:

7

Step-by-step explanation:

(7^{\frac{1}{2}})^2 = (\sqrt{7})^2 = \sqrt{7} \times \sqrt{7} = \sqrt{7 \times 7} = \sqrt{49} = 7

fredd [130]3 years ago
4 0

Answer:

7

Step-by-step explanation:

We can multiply the exponents so (7¹⁺²)² = 7⁽¹⁺² * ²⁾ = 7¹ = 7.

You might be interested in
_% of 1.50 = 0.30?<br> Im confused
ELEN [110]
0.30/1.50= 0.2= 20%
20%<span> of 1.50 = 0.30</span>
5 0
3 years ago
Read 2 more answers
Stacy wants to make 100 name tags with ribbons attached to them. each name tag requries 5 centimeter of ribbon. she has 3.25 met
nydimaria [60]
So convert 3.25 meters to centimeters, and you get 325 centimeters.
Now divide 325 by 5 (for each ribbon), and you get 65 name tags.
Therefore, she needs 35 MORE name tags to get to 100.
Multiply 35 by 5 and you get 175 MORE centimeters of ribbon.

Hope this helped!
4 0
4 years ago
Please help!!!
Kay [80]

Answer:3.125

Step-by-step explanation: You have to divide 28 by 8

8 0
3 years ago
Help, i know the answer but i don’t know how to do the work
Diano4ka-milaya [45]

Answer:

C

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying each radical before combining them.

\sqrt{45t}

= \sqrt{9(5t)}

= \sqrt{9} × \sqrt{5t} = 3\sqrt{5t}

-----------------------------------------------------------------------------

\sqrt{125t}

= \sqrt{25(5t)}

= \sqrt{25} × \sqrt{5t} = 5\sqrt{5t}

---------------------------------------------------------------------------

Hence

2(3\sqrt{5t}) - 3(5\sqrt{5t}

= 6\sqrt{5t} - 15\sqrt{5t}

= - 9\sqrt{5t} → C

7 0
4 years ago
I’m having troubles with this one.
nikklg [1K]

Answer:

239 degrees.

Arc is circumference so length = r * 4.17133691221

Step-by-step explanation:

We eliminate RSQ in degrees = 90 + 31 = 121

So that;

RPQ = 360 -121 = 239 degrees

2pi radius (239/360) = r6.28318530718 (0.66388888888)

= r * 4.17133691221

7 0
4 years ago
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