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alexandr402 [8]
3 years ago
6

144 is the product of -12 and q

Mathematics
2 answers:
Luba_88 [7]3 years ago
7 0
A is equal to -12 as two negatives multiplied together form a positive and 12 times 12 is 144
koban [17]3 years ago
4 0

Answer:

Step-by-step explanation:

Ok

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No irrational numbers are whole numbers true or false
Tatiana [17]
  Irrational numbers are real numbers that can not be made by dividing 2 integers, like π , √2, √3, ...
  And whole numbers are rational. For example: 5 can be written as 5 / 1.
  Answer:
  No irrational numbers are whole numbers.
  True.
7 0
3 years ago
Which equations can pair with y = 3x - 2 to create<br> a consistent and independent system?
Aloiza [94]

Answer:

y = 4x - 4 is one equation.

Step-by-step explanation:

You haven't given a list but we can create one equation:

If a system of equations have one solution they are consistent and independent.

Finding an equation  to pair with y = 3x - 2 to create this :-

Let x = 2 then y = 3(2) - 2 = 4.

So our equation will  also have this solution.

One equation could be:

y = 4x  - 4.

4 0
3 years ago
Read 2 more answers
Use the graph to find the slope (m) and y-intercept (b)
irga5000 [103]

Answer:

Slope=4 y-intercept=(0,-21) or -21

Step-by-step explanation:

To find<u> slope</u>

m=-13-(-17)/2-1

m=4/1

m=4

To find <u>y-intercept</u>

y-(-17)=4(x-1)

y+17=4(x-1)

y+17=4x-4

Subtract both sides by 17

y=4x-21

y-intercept=-21

8 0
3 years ago
Find the volume of the solid generated by revolving the region in the first quadrant bounded by the coordinate​ axes, the curve
Salsk061 [2.6K]

Answer:

\large \boxed{2\pi(15 - \ln16)}

Step-by-step explanation:

A 90° portion of your volume is shown below.

Let's use the shell method and decompose the solid of revolution into cylindrical shells.

The volume of each cylindrical shell is

dV = 2πrh dx

where  

r = ln16 - x

h = eˣ

So

dV = 2π(ln16 - x)eˣdx  

\begin{array}{rcl}V& =& 2\pi \int_{0}^{\ln16}(\ln16 - x)e^{x}dx\\\\&=&2\pi \int_{0}^{\ln16}(\ln 16)e^{x}dx -2\pi \int_{0}^{\ln16} xe^{x}dx\\\\&=& 2\pi \ln16 \int_{0}^{\ln16}e^{x}dx - 2\pi\int_{0}^{\ln16}xe^{x}dx\\\\\end{array}

Let's integrate the two terms separately.

\begin{array}{rcl}A &=& 2\pi \ln16 \int_{0}^{\ln16}e^{x}dx\\\\&=& 2\pi\ln16[e^{x}]_{0}^{\ln16}\\\\&=& 2\pi\ln16(16 - 1)\\&= &\mathbf{30\pi\ln1}\\\\B &=&2\pi\int_{0}^{\ln16}xe^{x}dx\\\end{array}

Use the integration by parts formula

\int u dv  = uv - \int v du

\begin{array}{rcl}uv - \int v du &=&\\B &=& 2\pi[xe^{x}]_{0}^{\ln16} - 2\pi \int_{0}^{\ln16} e^{x}dx\\\\&=&2\pi[xe^{x}]_{0}^{\ln16}-2\pi [e^{x}]_{0 }^{\ln16}\\\\&= &2\pi(16\ln16- 0) -2\pi(16 - 1)\\&=& \mathbf{32\pi \ln16 -30\pi}\\A - B &= &30\pi\ln16 - 32\pi \ln16 +30\pi\\&=& 30\pi - 2\pi \ln16\\&=&\mathbf{2\pi(15 - \ln16)}\end{array}\\\text{The volume of the solid is $\large \boxed{\mathbf{2\pi(15 - \ln16)}}$}

7 0
4 years ago
All you need is in the photo ​
Deffense [45]

Answer:

Bottom to top -

0,-3

0,1

1,2

7 0
3 years ago
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