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STALIN [3.7K]
3 years ago
11

Do inequalities have a range of solutions

Mathematics
1 answer:
marshall27 [118]3 years ago
4 0

Answer:

They do often times. There's not really much to tell about it. They can have multiple, they can go on and on.

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Pls answer this with an explanation if you can
Rasek [7]

Answer: 7 to 4

Step-by-step explanation: There are 16+12=28 total students, and 16 boys. Therefore, the ratio is 28:16, but you must simplify that, you can do this by dividing both values by 4 to get 7:4.

7 0
3 years ago
Solve the given equation.<br><br><br><br> 3y = 51<br> what is y?
SashulF [63]

Answer:

y=17

Step-by-step explanation:

51/3

Hope this helps!

6 0
3 years ago
How dot figure out the perimeter of Question 2, a
lora16 [44]

Answer:

51.96 mm

Step-by-step explanation:

Perimeter of circle = 2 × pi × r

Perimeter of small circle

= 2 × 3.14 × 10/2

= 31.4 mm

half of perimeter of small circle = 31.4/2 = 15.7 mm

Perimeter of large circle

= 2 × 3.14 × (5+4)

= 2 × 3.14 × 9

= 56.52

half of perimeter of large circle = 56.52/2 = 28.26 mm

All line = half line small circle + half line large circle + (4 × 2)

All line = 15.7 + 28.26 + 8

= 51.96 mm

7 0
3 years ago
9. Combine the radical expression, if possible.
Anastaziya [24]

Answer:

we conclude that:

3\sqrt{125}+4\sqrt{20}=23\sqrt{5}    

Hence, the last option i.e. 23\sqrt{5} is correct.                      

Step-by-step explanation:

Given the expression

3\sqrt{125}+4\sqrt{20}

Combining the radical expressions

3\sqrt{125}+4\sqrt{20}

let us first solve

3\sqrt{125}

=3\sqrt{5^3}

=3\sqrt{5^2\cdot \:5}

Apply radical rule:  \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0

=3\sqrt{5^2}\sqrt{5}

Apply radical rule:   \sqrt{a^2}=a,\:\quad \:a\ge 0

=3\cdot \:5\sqrt{5}

=15\sqrt{5}

Thus,

3\sqrt{125}=15\sqrt{5}

similarly solving

4\sqrt{20}

=4\sqrt{2^2\cdot \:5}

Apply radical rule:  \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0

=4\sqrt{2^2}\sqrt{5}

Apply radical rule:   \sqrt{a^2}=a,\:\quad \:a\ge 0

=4\cdot \:2\sqrt{5}

=8\sqrt{5}

Thus,

4\sqrt{20}=8\sqrt{5}

so we get

3\sqrt{125}=15\sqrt{5}

4\sqrt{20}=8\sqrt{5}

so the expression becomes

3\sqrt{125}+4\sqrt{20}=15\sqrt{5}+8\sqrt{5}        ∵ 3\sqrt{125}=15\sqrt{5} , 4\sqrt{20}=8\sqrt{5}

                        =23\sqrt{5}                   ∵ 15\sqrt{5}+8\sqrt{5}=23\sqrt{5}

Therefore, we conclude that:

3\sqrt{125}+4\sqrt{20}=23\sqrt{5}    

Hence, the last option i.e. 23\sqrt{5} is correct.                    

7 0
3 years ago
10 points
Tems11 [23]
The answer should be 37
6 0
3 years ago
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