Question

Solve the quadratic equation:

Answer 1

Answer:

           The last x=-5 or x=-2

Step-by-step explanation:

$x^2+7x+10=0\qquad\implies\quad a=1\,,\ b=7\,,\ c=10\\\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-7\pm\sqrt{7^2-4(1)(10)}}{2(1)}=\dfrac{-7\pm\sqrt{49-40}}{2}=\dfrac{-7\pm\sqrt9}{2}\\\\ x_1=\dfrac{-7+3}2=\dfrac{-4}2=-2\,,\qquad x_1=\dfrac{-7-3}2=\dfrac{-10}2=-5$