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katen-ka-za [31]
3 years ago
14

Let (8,−3) be a point on the terminal side of θ. Find the exact values of cosθ, cscθ, and tanθ.

Mathematics
1 answer:
denis23 [38]3 years ago
6 0

Answer:

\text{Cos}\theta=\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}

\text{Csc}\theta=-\frac{\sqrt{73}}{3}

\text{tan}\theta =\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}

Step-by-step explanation:

From the picture attached,

(8, -3) is a point on the terminal side of angle θ.

Therefore, distance 'R' from the origin will be,

R = \sqrt{x^{2}+y^{2}}

R = \sqrt{8^{2}+(-3)^2}

  = \sqrt{64+9}

  = \sqrt{73}

Therefore, Cosθ = \frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}

Sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{y}{R}=\frac{-3}{\sqrt{73} }

tanθ = \frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}

Cscθ = \frac{1}{\text{Sin}\theta}=\frac{R}{y}=-\frac{\sqrt{73}}{3}

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