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kirill115 [55]
3 years ago
8

Which of the following represents the most accurate estimation if 75-33?

Mathematics
2 answers:
guapka [62]3 years ago
8 0
You could round 75 to 80 and 33 to 30. Then subract to get 50
Alja [10]3 years ago
4 0
40 is the most accurate.
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Twice the quantity b plus 9
mojhsa [17]

Answer:

2b+9

Step-by-step explanation:

Twice the quantity b is 2*b = 2b

...and then you add 9 which is:

2b+9

5 0
2 years ago
The drama club is selling candles for a fundraiser. They spend $100 on the candles and sell them for $4.50 each. How many candle
IrinaVladis [17]
So we know that they spend $100 on the candles. In order to make a $125 profit, they must sell $225 worth of candles. Each candle sells for $4.50, so:
4.5x > 225 is the inequality for that. It just means $4.50 times the number of candles has to be more than the $225 we need. To simplify it, just divide both sided by 4.5:
x > 50
They have to sell more than 50 candles. Make sense?
7 0
3 years ago
Read 2 more answers
Have I been solving these equations correctly?
Tresset [83]

14)


2(-3)² => 2(-3)(-3) => 2*9 = > 18


27+18-11 => 27 + 7 = > 34.


16)


\bf p(x)=\cfrac{x^2-4}{2x+1}\implies p(-8)=\cfrac{(-8)^2-4}{2(-8)+1}\implies p(-8)=\cfrac{64-4}{-16+1} \\\\\\ p(-8)=\cfrac{60}{-15}\implies p(-8)=-4


17)


\bf h(x)=3\cdot 9^x\implies h(-2)=3\cdot 9^{-2}\implies h(-2)=3\cdot \cfrac{1}{9^2} \\\\\\ h(-2)=\cfrac{3}{9^2}\implies h(-2)=\cfrac{3}{81}\implies h(-2)=\cfrac{1}{27}

4 0
3 years ago
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
I need the answer to this fast<br> Please
jeyben [28]
The initial function is slope

=> slope = 7-1/6-0 = 6/6 = 1

Hope this helps you :)
5 0
2 years ago
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