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natta225 [31]
1 year ago
11

Writing an equation of a probably given the vertex and focus

Mathematics
1 answer:
White raven [17]1 year ago
6 0

The equation of the vertical parabola in vertex form is written as

y=\frac{1}{4p}(x-h)^2+k

Where (h, k) are the coordinates of the vertex and p is the focal distance.

The directrix of a parabola is a line which every point of the parabola is equally distant to this line and the focus of the parabola. The vertex is located between the focus and the directrix, therefore, the distance between the y-coordinate of the vertex and the directrix represents the focal distance.

p=1-6=-5

Using this value for p and (3, 1) as the vertex, we have our equation

y=-\frac{1}{20}(x-3)^2+1

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Part 1
We are given x^2-21x=-4x. This can be rewritten as x^2-18x=0.
Therefore, a=1, b=-18, c=0.
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The values of x are
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Part 2
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Part 3.
The first equation is y=x^2+2.
The second equation is y=3x+20.

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     \left(x-6\right)\left(x+3\right)=0
Equating both factors to zero.
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When the value of x is 6, the value of y is 
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When the value of x is -3, the value of y is 
     y=3\left(-3\right)+20=11

Therefore, the solutions are (6,38) or (-3,11)
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