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2 years ago

Function Question!!!!!!!!

Mathematics

1 answer:

Artist 52 [7]2 years ago

3 0

Choice A) The vertical line test confirms that the graph is a function
True. It is impossible to pass a single vertical line through more than one point on this graph.
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Choice B) The domain is x >= 2
False. The domain is the set of all real numbers
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Choice C) The range is y >= 2
True. The smallest y value possible is y = 2. This is where the lowest part of the graph occurs.
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Choice D) This piecewise function is made up of four intervals
False. There are two intervals (the curved one on the left; the straight piece on the right)
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Choice E) Each interval of the piecewise function contains a graph of a linear function.
False. While the piece on the right is linear, the left portion is nonlinear (curved piece).
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In summary we have:

choice A) true
choice B) false
choice C) true
choice D) false
choice E) false

So the answers are choice A and choice C

You might be interested in

Is the quotient of two integers always a rational number? Explain.

Troyanec [42]

Answer:

It is true that the quotient of two integers is always a rational number. This is because a rational number is any number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

4 0

3 years ago

The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm197.5 cm and a standard deviation

fiasKO [112]

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 197.5, \sigma = 8.3$

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{210.9 - 197.5}{8.3}$

$Z = 1.61$

$Z = 1.61$ has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now $n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14$

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{196 - 197.5}{2.14}$

$Z = -0.7$

$Z = -0.7$ has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

5 0

3 years ago

4. (03.03 HC)

Kitty [74]

Answer:

A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones

Step-by-step explanation:

B. table : (8,8)(12,12)(14,16)(16,16)

look at ur points...when x = 8, y = 8...so the table, when x = 8 has a

value of 8

relation : f(x) = 8x - 5....when x = 8

f(8) = 8(8) - 5

f(8) = 64 - 5

f(8) = 59....and the relation has a value of 59

Therefore, the relation has a greater value when x = 8 <==

C. f(x) = 8x - 5...when f(x) = 19

19 = 8x - 5

19 + 5 = 8x

24 = 8x

24/8 = x

3 = x <==

7 0

3 years ago

Jane is X years old. How old will she be in 2 year's time? How old will she be in 5 year's time?

ch4aika [34]

Answer:

Jane's age = X

In 2 years time = X + 2

In 5 years time = X + 5

Step-by-step explanation:

Answer from Gauth math

6 0

2 years ago

Read 2 more answers

Rewrite the function in standard form.<br> f(x)= 3(x + 5)2 - 7

Anna007 [38]

Answer: F= 29
Explanation: first use distributive property and multiplied by three with the parentheses. And then multiply to by what you just solved. Remember to keep writing everything that we haven’t used yet. Then divide both the left side and the 6X by X. Then subtract 30 by 7. And add six. I hope this helped

3 0

2 years ago