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nikdorinn [45]
3 years ago
14

Function Question!!!!!!!!

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0
Choice A) The vertical line test confirms that the graph is a function
True. It is impossible to pass a single vertical line through more than one point on this graph. 
--------------------------------------------
Choice B) The domain is x >= 2
False. The domain is the set of all real numbers
--------------------------------------------
Choice C) The range is y >= 2
True. The smallest y value possible is y = 2. This is where the lowest part of the graph occurs.
--------------------------------------------
Choice D) This piecewise function is made up of four intervals
False. There are two intervals (the curved one on the left; the straight piece on the right)
--------------------------------------------
Choice E) Each interval of the piecewise function contains a graph of a linear function.
False. While the piece on the right is linear, the left portion is nonlinear (curved piece).
--------------------------------------------
In summary we have:

choice A) true
choice B) false
choice C) true
choice D) false
choice E) false

So the answers are choice A and choice C

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Find the composition of
Rus_ich [418]

Answer:

[(x + 6), (y + 1)]

Step-by-step explanation:

Vertices of the quadrilateral ABCD are,

A → (-5, 2)

B → (-3, 4)

C → (-2, 4)

D → (-1, 2)

By reflecting the given quadrilateral ABCD across x-axis to form the image quadrilateral A'B'C'D',

Rule for the reflection of a point across x-axis is,

(x, y) → (x , -y)

Coordinates of the image point A' will be,

A(-5, 2) → A'(-5, -2)

From the picture attached, point E is obtained by translation of point A'.

Rule for the translation of a point by h units right and k units up,

A'(x+h, y+k) → E(x', y')

By this rule,

A'(-5 + h, -2 + k) → E(1, -1)

By comparing coordinates of A' and E,

-5 + h = 1

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-2 + k = -1

k = 1

That means

Rule for the translation will be,

[(x + 6), (y + 1)]

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