Given:
The graph of a function 
.
To find:
The interval where 
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for 
and 
.
The function between x=0 and x=3.6 lies below the x-axis. So, 
for 
.
Now,
For 
, the graph of h(x) is above the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
Answer:
2 to the sixth, 4 to the third, 8 squared
Step-by-step explanation: 2*2*2*2*2*2=64 because you would have 2, 4,8,16,32,64
4*4*4=64 because you would have 4,16,64
8*8=64
Answer:
Choice A
Step-by-step explanation:
(4m^5n^2/m^2n)^3
dividing exponents = subtraction
(4m^3n)^3
4^3 = 64
(m^3 )^3 = m^3x3 = m^9
64m^9n^3
The scale faction is 20 to 1 hope that helps
