Answer:
(a) 0.5899
(b) 0.9166
Step-by-step explanation:
Let X be the random variable that represents the height of a woman. Then, X is normally distributed with
= 62.5 in
= 2.2 in
the normal probability density function is given by
, then
(a) 
= 0.5899
(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)
(b) We are seeking 
where n = 37. 
is normally distributed with mean 62.5 in and standard deviation 
. So, the probability density function is given by
, and
= 0.9166
(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))
You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.
Answer: $6.48
Step-by-step explanation:
1.60 * 0.1 = $0.16
1.60 - 0.16 = $1.44
1.44 * 4.5 = $6.48
Answer:
FOR REGULAR PYRAMID with those dimension.
L.A = 96
FOR HEXAGONAL PYRAMID with those dimension
L.A = 171.71
Step-by-step explanation:
Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.
Hence I solved for both:
FOR REGULAR PYRAMID
Lateral Area (L.A) = 1/2* p * l
Where p = Perimeter of base
P = 4s
P = 4 * 6
P = 24cm
l = slanted height
l = 8cm
L.A = 1/2 * 24 * 8
L.A = 1/2 ( 192)
L.A = 96cm ^ 2
FOR AN HEXAGONAL PYRAMID
Lateral Area = 3a √ h^2 + (3a^2) / 4
Where:
a = Base Edge = 6
h = Height = 8
L.A = 3*6 √ 8^2 + ( 3*6^2) / 4
L.A = 18 √ 64 + ( 3 * 36) / 4
L.A = 18 √ 64 + 108/4
L.A = 18 √ 64+27
L.A = 18 √ 91
L.A = 18 * 9.539
L.A = 171.71
Answer:
Nope :)
Step-by-step explanation:
Answer: population size= 10
Mean= 167
MAD= 32
Step-by-step explanation:
