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Jlenok [28]
3 years ago
11

Select the correct answer

Mathematics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

this is correct on plato/edmentum

Step-by-step explanation:

Anettt [7]3 years ago
7 0

Answer:

i got it right on the test

Step-by-step explanation:

You might be interested in
Simplify (2z^5)(12z^3)/4z^4
Sphinxa [80]

Answer:

6z^{4}

Step-by-step explanation:

Given in the question an expression,

\frac{ (2z^5)(12z^3)}{4z^4}

Step 1

Apply exponential "product rule"

x^{m}x^{n}=x^{m+n}

\frac{ 12(2)z^5)(z^3)}{4z^4}

\frac{ (24)z^5)(z^3)}{4z^4}

\frac{ 24(z^{(5+3)})}{4z^4}

\frac{ 24(z^{8})}{4z^4}

Step 2

Apply exponential " divide rule"

\frac{x^{m}}{x^{n}}=x^{m-n}

\frac{24/4(z^{8})}{z^4}

\frac{6(z^{8})}{z^4}

\frac{6(z^{8-4})}{1}

6z^{4}

5 0
3 years ago
Someone i need help i cant expand these expressions
vovangra [49]

Answer: The answer is 5x+6

Step-by-step explanation:

1/3(9x+16+2)+2x

= 1/3(9x)+1/3(16)+1/3(2)+2x

=3x/1+16/3+2/3+2x/1

=3x/1+2x/1+16/3+2/3

Take the L.C.M

=3x+2x/1+16+2/3

=5x/1+18/3

=5x+6

4 0
3 years ago
The table and graph below show the amount of money Mi-Ling and Daniel
Over [174]
Is there a math question and can you show it please
6 0
3 years ago
Which expression is equivalent to 11 - (-3 5/8)
faust18 [17]

Answer:

14.63

the number is rounded up it was origannaly 14.625

6 0
3 years ago
Etermine two pairs of polar coordinates for the point (2, -2) with 0° ≤ θ < 360°.
Jet001 [13]

To convert from rectangular to polar we will use these 2 formulas:

r^2=x^2+y^2 and

tan\theta=\frac{y}{x}.

The r value found serves as the first coordinate in our polar coordinate, and the angle serves as the second coordinate of the pair. We are told to find 2. Since the r value will always be the same (it's the length of the hypotenuse created in the right triangle we form when determining our angle theta), the angle is what is going to be different in our coordinate pairs. We use the x and y coordinates from the given rectangular coordinate to solve for the r in both our coordinate pairs.

r^2=2^2+ -2^2 which gives us an r value of 2\sqrt{2}. That's r for both coordinate pairs. Now we move to the angle. Setting up according to our formula we have

tan\theta =\frac{-2}{2} =-1.

This asks the question "what angle(s) has/have a tangent of -1?". That's what we have to find out! Since the tangent ratio is y/x AND since it is negative, it is going to lie in a quadrant where x is negative and y is positive, AND where x is positive and y is negative. Those quadrants are 2 and 4. In QII, x is negative so the tangent ratio is negative here; in QIV, y is negative so the tangent ratio is negative here as well. Now, if we type inverse tangent of -1 into our calculators in degree mode, we get that the angle that has a tangent of -1 is -45. Measured from the positive x axis, -45 does in fact go into the fourth quadrant. However, since the inverse tangent of -1 is -45, we also have a 45 degree angle in the second quadrant. Those are reference angles, mind you. A 45 degree angle in QII has a coterminal angle of 135 degree; a 45 degree angle in QIV has a coterminal angle of 315. If you don't understand that, go back to your lesson on reference angles and coterminal angles to see what those are. So our polar coordinates for that rectangular coordinate are

(2\sqrt{2},135) and

(2\sqrt{2},315)

8 0
3 years ago
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