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3 years ago

HELP ME PLS I NEED TO PASS THIS TEST OR I FAIL 8TH GRADE

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

7 0

<span>----
Solve for "x":
x + 4y = 24
x + 16 = 24
x = 8
-----------------
Solution: (8,4)</span>

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(3√5 + 4√2)(√5 + √2）<br>

olga nikolaevna [1]

Answer:

Step-by-step explanation:

3√5*√5+3√5*√2+ 4√2*√5+ 4√2*√2

15 +3√10 + 4√10 + 8

23+7√10

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3 years ago

Solve this equation <br>(3m⁴)²

earnstyle [38]

Answer:

9m⁸

Step-by-step explanation:

3^2=9

(m⁴)² = m⁸

9*m⁸

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3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

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3 years ago

An opinion poll asked participants if they watched a particular television show. Of the 80 participants, 30 were male and 50 wer

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what's the question?

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Brenton’s weekly pay, P(h) , in dollars, is a function of the number of hours he works, h. He gets paid $20 per hour for the fir

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Answer:

{h| 0 ≤ h ≤ 60}

Step-by-step explanation:

Next time, please separate the possible answer choices with commas or semi-colons, or put them on separate lines.

The second set says it all: {h| 0 ≤ h ≤ 60}. This guy cannot work more than 60 hours per week, and h cannot be negative.

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3 years ago

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