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GalinKa [24]
3 years ago
8

3. Error Analysis Isabel says that the equation x - 2 = -(x - 2) has no

Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Given:

The equation is

(x-2)=-(x-2)

Isabel says that the given equation has no  solution because a number can never be equal to its opposite.

To find:

Isabel's mistake.

Solution:

Her reason "a number can never be equal to its opposite" is not correct.

Zero is a number that can be equal to its opposite.

So, the given equation has solution for which LHS=RHS=0.

We have,

(x-2)=-(x-2)

x-2=-(x)-(-2)

x-2=-x+2

Add x and 2 on both sides.

x-2+x+2=-x+2+x+2

2x=4

Divide both sides by 2.

x=\dfrac{4}{2}

x=2

So, the given equation has a solution x=2.

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Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0
erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

15x^2-kx+1=0           (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0
3 years ago
I’ll give brainliest if you answer quick!!!
Katarina [22]

Area is square units, so the new area would be the scale factor squared:

Scale factor is 2, so the area would increase by 2^2 = 4

The answer is B.4

3 0
3 years ago
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3/10÷4/5 im just lost
oee [108]

Answer:

0.375

Step-by-step explanation:

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5 0
2 years ago
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Given the function g(x) = x^3 − (8+1)x^2-4(9+2)x+(5x2-1) determine where the function is quickly(slowly) increasing (decreasing)
Elenna [48]

Answer:

hence g(x) is increasing at point x= 3+14i,3-14i

Step-by-step explanation:

given, g(x)=x^3-(8+1)x^2-4(9+2)x+5x2-1

         g(x)=x^3-9x^2-44x+10x-1

         g(x)=x^3-9x^2-34x-1

   \frac{\partial g(x)}{\partial x}=3x^2-18x-34

for increasing and decreasing function,

3x^2-18x-34=0

x=3+14i \geq0

x=3-14i \geq0

hence g(x) is increasing at point x= 3+14i,3-14i answer

3 0
3 years ago
Pleaseeee help meee<br>How to solve this questions?<br><br>(i) ?<br>(ii) ?
aalyn [17]
(i) The scale factor is 6 because of the ratio between the 2 given corresponding sides.
I don't know the second part, but I hope this helps regardless.

8 0
3 years ago
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