Find three consecutive even integers such that the product of the first and the third is 96
2 answers:
2Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
x,x+2,x+4 are the consecutive even integers
x(x+4)=96
X^2 +4x =96
x^2 +4x =96
x^2 +12x-8x -96=0
x(x+12)-8(x+12)=0
(x+12)(x-8)=0
Therefore x=8 or-12
x=8
Consecutive even integers are 8,10,12
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