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3 years ago

Is something with/without a decimal greater?

Mathematics

2 answers:

qaws [65]3 years ago

7 0

Answer:

without

Step-by-step explanation:

Anything without a decimal is greater than something that does.

Maksim231197 [3]3 years ago

3 0

Answer:

without

Step-by-step explanation:

If it has no decimal, it is greater than a number with a decimal. The answer is without.

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Elizabeth has 14 boxes of cookies each box has 28 cookies how many cookies does she have

aev [14]

We calculate this by multiplying the number of cookies by the number of boxes:

28*14=(20+8)*14=280+80+32=360+32=392 (that's how I like to count it, there are also other methods)

so she has 392 cookies in common.

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4 years ago

Help please 50P wrong answer gets removed!!!!

RSB [31]

Answer:

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Step-by-step explanation:

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3 years ago

What is the answer for -4 (-6x + 3 ) =12

liq [111]

Answer:

x=1

Step-by-step explanation:

Simplify:

24x-12=12

add 12 on both sides:

24x=24

divide both sides by 24

x=1

Hope this helps!

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3 years ago

A store is offering a 20% discount on all items. Is there a proportional relationship between the original price of an item and

professor190 [17]

Answer:

A store is offering a 14% discount on all items. Write an equation relating the sale price S for an item to its list price L.

Step-by-step explanation:

8 0

3 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago