Answer:
f(g(-8)) = -26
Step-by-step explanation:
Given:
f(x)=2x and g(x)=2x+3
Required:
f(g(-8))=?
Solution:
First we will find g(-8)
g(x) = 2x+3
g(-8)= 2(-8)+3
= -16 + 3
= -13.
so, g(-8) = -13
Now, for calculation f(g(-8)) we can put the value of g(-8) i.e, -13
so, f(x) = 2x
f(-13) = 2(-13)
= -26
so, f(-13) = -26
and f(g(-8)) = -26
Based on the statement below, if d is the midpoint of the segment AC, the length of the segment AB is 4.5cm.
<h3>What is the line segment about?</h3>
in the question given,
AC = 3cm,
Therefore, AD and DC will be = 1.5cm segments each.
We are given C as the midpoint of segment DB.
So CB = 1.5cm.
The representation of the line segment is:
A-----------D------------C-------------B
1.5 1.5 1.5
Since AD, DC and CB are each 1.5cm segments. Then the equation will be:
= 1.5 + 1.5 + 1.5
= 4.5
Therefore, The length of the segment AB is 4.5cm.
See full question below
If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm.
Learn more about midpoint from
brainly.com/question/10100714
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Answer:
4
Step-by-step explanation:
If Judge is x years old and Eden is 6 years older, then Eden is x + 6 years old.
The second part tells us that Eden will be twice as old as Judge in two years.
This means that in two years: (Eden's age) = 2 * (Judge's age).
Since we know that Eden's age can be represented as x + 6 and Judge's age can be represented as x, we can write this: x + 6 = 2 * x
Simplify the equation:
x + 6 = 2x
6 = x = Judge's age (in two years)
If Judge is 6 two years later, then he must be 4 now.
To check our work, we can just look at the problem. Judge is 4 years old and Eden is 6 years older than Judge (that means Eden is 10 right now). Two years later, Eden is 12 and Judge is 6, so Eden is twice as old as Judge. The answer is correct.
Answer:
Step-by-step explanation:
a)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,r =50
rate of change of area =dA/dt =2 pi *50 *25 =2500pi=7854
area growing 7854 cm2/s
b)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,A =64
pi r^2 =64
=>r =8/√pi
rate of change of area =dA/dt =2 pi *(8/√pi) *25 =400√pi=708.98
area growing 708.98 cm2/s