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4 years ago

Find the first, fourth, and eighth terms of the sequence. A(n) = –5 • 3n–1 please help me

Mathematics

2 answers:

Korvikt [17]4 years ago

6 0

Answer:

First term: -10

Fourth term: -55

Eighth term: -115

Step-by-step explanation:

I am assuming the means -5(3n-1). To find the first term, plug in 1. You will get -5(3*1-1) or -5*2 or -10.

To find the fourth term, plug in 4. You will get -5(3*4-1) or -5*11 or -55.

To find the eighth term, plug in 8. You will get -5(3*8-1) or -5*23 or -115.

So the answers are -10, -55, and -115.

Ivenika [448]4 years ago

5 0

Answer:

-5, -135, -10935

Step-by-step explanation:

just bc

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The function f(x) is shown in this graph.

Alexus [3.1K]

Answer:

A maybe?

Step-by-step explanation:

by looking at the graph you can see there are two points with one being at (0, 3) (given) and the other being at (1, 1) (by looking at the graph). You can use the slope formula (y2 - y1) / (x2 - x1) which gives you the slope.

Plug Values In:

(1-3) / (1-0) = -2/1 = -2

slope of f(x) = -2

slope of g(x) = -7 (slope-intercept form y=mx+b where m is the slope and b is the y-intercept)

I'm honestly not quite sure what it means by greater than since technically the slope of f(x) is greater than the slope of g(x) but does it mean how much it's changing by in which case the sign doesn't matter. Although I'm just going to assume it purely means the value in which case A is true.

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2 years ago

What’s the difference between a 16-ounce brick and a carpenter

NNADVOKAT [17]

One weighs a pound and the other pounds away!

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3 years ago

Out of six computer chips, two are defective. If two chips are randomly chosen for testing (without replacement), compute the pr

Ratling [72]

Answer:

The probability that of the two chips selected both are defective is 0.1089.

Step-by-step explanation:

Let X = number of defective chips.

It is provided that there are 2 defective chips among 6 chips.

The probability of selecting a defective chip is:

$P(X)=p=\frac{2}{6}=0.33$

A sample of n = 2 chips are selected.

The random variable X follows a Binomial distribution with parameter n = 2 and p = 0.33.

The probability function of a Binomial distribution is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...$

Compute the probability that of the two chips selected both are defective as follows:

$P(X=2)={2\choose 2}(0.33)^{2}(1-0.33)^{2-2}=1\times 0.1089\times 1=0.1089$

Thus, the probability that of the two chips selected both are defective is 0.1089.

The sample space of selecting two chips is:

S = (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5)

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3 years ago

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bixtya [17]

Answer:

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Step-by-step explanation:

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3 years ago

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grigory [225]

Answer:

Step-by-step explanation:

Inside the figure is a right triangle with hypotenuse 18 cm. Its height is half the measure of the side length. 18.2 is 9 cm. Using 9 cm and 18 cm, substitute the values into the Pythagorean theorem.

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4 years ago

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