<h3>
Answer: 12/25</h3>
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Reason:
60% = 60/100 = 0.6 is the probability of making any given free-throw.
1 - 0.6 = 0.4 is the probability of missing any given free-throw.
We have these probabilities
- A = P(making 1st, missing 2nd) = 0.6*0.4 = 0.24
- B = P(missing 1st, making 2nd) = 0.4*0.6 = 0.24
The probability of making exactly one free throw is A+B = 0.24+0.24 = 0.48
Convert this to a fraction:
0.48 = 48/100 = (4*12)/(4*25) = 12/25
56x² - 49x + 14 = 7(8x² - 7x +2)
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The greatest common factor of 56, 49, and 14 is 7.
Answer: B
Step-by-step explanation:
Division of components are consistent - the same
The mass of brick is 2478 gram
<em><u>Solution:</u></em>
A brick is in the shape of a rectangular prism with a length of 8 inches, a width of 3.5 inches, and a height of 2 inches
Length = 8 inches
Width = 3.5 inches
Height = 2 inches
<em><u>The volume of rectangular prism is given as:</u></em>
Thus volume of brick is 56 cubic inches
<em><u>Convert inches to centimeter</u></em>
1 inch = 2.54 centimeter
Therefore,
56 cubic inches = 56 x 2.54 x 2.54 x 2.54 cubic centimeter
56 cubic inches = 917.676 cubic centimeter
Thus, we get,
volume = 917.676 cubic centimeter
The brick has a density of 2.7 grams per cubic centimeter
Density = 2.7 grams
<em><u>The mass of brick is given by formula:</u></em>
<em><u>Substituting the values we get,</u></em>
Thus mass of brick is 2478 gram
We can set up an equation to solve this problem. I am setting the number of marbles in a red jar to R.
R + R + R - 16 = 41
We solve this by adding 16 to both sides and combining all of the R terms.. This gives us:
3R = 57
We can finish this problem by dividing both sides by 3.
R = 19. So, there are 19 marbles in a red jar.
We can easily figure out how many marbles are in a blue jar by subtracting the total amount of marbles in 2 red jars from the total amount of marbles. I am setting the amount of marbles in a blue jar to B.
41 - 19*2 = B
B = 3
So, there are 3 marbles in a blue jar and 19 marbles in a red jar.
