How do you find the slop from this?

Mathematics

2 answers:

marta [7]4 years ago

5 0

Take two of the coordinates located on the graph and perform the rise over run technique. you can also subtract Y2-Y1 over X2-X1. hope this helps!

lisabon 2012 [21]4 years ago

4 0

Answer:

Look at the rise over run

itd be 10/10 or 1

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Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

3 years ago

I really need help and i need to solve this one that says solve & simplify:3/4×2/3

VARVARA [1.3K]

3/4 2/3

This is a multiplication of fractions

1.- Multiply the numerators and the denominators

3/4 x 2/3 = (3x 2) / (4 x 3)

= 6/12

2.- Simplify

= 3/6

= 1/2

4 0

1 year ago

Consider f(x)=3ax−x2. write down a formula in terms of a for the maximum of f(x).

lidiya [134]

For this case we have the following function:
$f (x) = 3ax-x ^ 2
$
To find the maximum of the function, what we should do is to derive the equation.
We have then:
$f '(x) = 3a-2x
$
We match zero:
$3a-2x = 0
$
We clear the value of x:
$2x = 3a

x = (2/3) a$
We substitute the value of x in the function to find the maximum:
$f ((2/3) a) = 3a ((2/3) a) - ((2/3) a) ^ 2
$
Rewriting:
$f ((2/3) a) = 2a ^ 2 - (4/9) a ^ 2

f ((2/3) a) = (18/9) a ^ 2 - (4/9) a ^ 2

f ((2/3) a) = (14/9) a ^ 2$
Answer:
a formula in terms of a for the maximum of f (x) is:
$f ((2/3) a) = (14/9) a ^ 2$