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Nadusha1986 [10]
3 years ago
8

WILL GIVE BRAINLIEST 5 = h/3 - 17 h = ? (h/3 is a fraction)

Mathematics
2 answers:
Nat2105 [25]3 years ago
7 0

Answer:

h = 66

Step-by-step explanation:

We are given the equation of one variable h and we have to solve the equation for h.

The equation is given by 5 = \frac{h}{3} - 17

⇒ 5 + 17 = \frac{h}{3} {Adding 17 to both sides}

⇒ 22 = \frac{h}{3}

⇒ h = 22 × 3 {Since we know that if \frac{a}{b} = c then we can write a = bc}

⇒ h = 66 (Answer)

marshall27 [118]3 years ago
3 0

Answer:

The value of h is 66.

Step-by-step explanation:

Given :

5 = \frac{h}{3} - 17

To find :

h = ?

Solution :

The equation is given as

5 = \frac{h}{3} -17\\

Now take -17 to the Left Hand Side so it becomes + 17

5 + 17 = \frac{h}{3}\\22 = \frac{h}{3}

Now multiply 22 and 3 on the left-hand side we get

22\times 3 = h\\

66 = h\\

∴ h = 66

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A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say <em>E </em>occurring is:

P (E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let <em>X</em> = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, <em>n</em> = 20.

Number of defective electric toothbrushes is, <em>x</em> = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

{20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

{3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

                                                            =\frac{3}{190}\\

                                                            =0.01579\\\approx0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0
3 years ago
WHAT IS THE ANSWER TO -2(y-3)=22
Eva8 [605]
-2(y-3)=22 
-2y+6=22
-2y=16
y=-8
8 0
2 years ago
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