The height on the wall a 15-foot ladder will reach if it is placed 3. 5 feet from the base of a wall is 14.6 feet.
Using Pythagoras theorem,
c² = a² + b²
where
c = hypotenuse
a and b are the other two legs
The ladder length represent the hypotenuse sides
The distance of the ladder to the base of the wall is one of the leg.
The height on the wall the 15 ft ladder reach is the other leg
Therefore,
a² = 15² - 3.5²
a² = 225 - 12.25
a = √212.75
a = 14.5859521458
a ≈ 14.6 feet
learn more on Pythagoras theorem: brainly.com/question/13734303?referrer=searchResults
Answer:
The answer is below
Step-by-step explanation:
The company cost (C) = 500000 + 5q.
The cost function is given as C = a + cx, where a is the fixed cost and b is the variable cost. Hence, from the company's cost function, the variable cost is 5 and the fixed cost is 500000. The selling price is given as 6. The break even volume is given by:
Break even volume = fixed cost / (selling price - variable cost) = 500000 / (6 - 5) = 500000 units
Answer:
About 7 miles a day?
Step-by-step explanation:
53.2-10= 43.2
43.2 divided by 6 is about 7.6. I’m just in middle school though :)
The distance between the two points is 22.14 units
<h3>How to determine the distance between the two points?</h3>
The endpoints of the line segment are given as
(4,9) and (11, -12)
This can be rewritten as
(x, y) = (4,9) and (11, -12)
The distance between the endpoints of the segment is then calculated using the following distance formula
distance = √[(x₂ - x₁)² + (y₂ - y₁)²]
Where
(x, y) = (4,9) and (11, -12)
Substitute the known values in the above equation, so, we have the following representation
Distance = √[(4 - 11)² + (9 + 12)²]
Evaluate
Distance = 22.14
Hence, the distance is 22.14 units
Read more about distance at
brainly.com/question/7243416
#SPJ1
Isosceles acute I believe. Correct me if I’m wrong!
