Question

A twelve-sided die with sides labeled through will be rolled once. Each number is equally likely to be rolled. What is the probability of rolling a number greater than ? Write your answer as a fraction in simplest form.

Answer 1

Complete Question:

A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled, what is the probability of rolling a number greater than 10?

Answer:

$P(T) = \frac{1}{6}$

Step-by-step explanation:

Given

Number of Sides = 12

Required

Probability of obtaining a side greater than 10

We start by listing out the sample space;

$S = \{1,2,3,4,5,6,7,8,9,10,11,12\}$

$n(S) = 12$

Next, we list out digits greater than 10; Represent this with T

$T = \{11,12\}$

$n(T) = 2$

Probability of T is calculated as follows;

$P(T) = \frac{n(T)}{n(S)}$

$P(T) = \frac{2}{12}$

Divide the numerator and denominator by 2

$P(T) = \frac{1}{6}$

Hence, the required probability is $\frac{1}{6}$