A number increased by 5
1 answer:
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Answer:
36 laps Ronnie swim during practice .
Step-by-step explanation:
Let us assume that the laps that Ronnie swims be x .
Let us assume that the laps that Jackie swims be y .
As given
For every 3 laps that Jackie swims, Ronnie swims 4 laps.
i.e
3 × laps that Ronnie swims = 4 × laps that Jackie swims
3 × x = 4 × y
3x = 4y
Equation becomes
x + y = 63
Thus by using 3x = 4y .
Thus
4x + 3x = 63 × 4
7x = 252
x = 36
Put the value of x in the equation x + y = 63
36 + y = 63
y = 63 - 36
y = 27
Therefore the 36 laps Ronnie swim during practice .
Let
A (x1,y1)-------> (1,5)
B (x2,y2)------> (5,10)
C (x3,y3)------> (9,15)
D (x4,y4)------> (13,20)
find the slope
AB
m=(10-5)/(5-1)-----> m=5/4
find the slope
CB
m=(15-10)/(9-5)-----> m=5/4
find the slope
DC
m=(20-15)/(13-9)-----> m=5/4
so
<span>the relationship shown is linear
</span>
<span>to model the data with an equation find the equation of a line
</span>with m=5/4 and point A (1,5)
y-y1=m*(x-x1)-----> y-5=(5/4)*(x-1)----> y=1.25x-1.25+5-----> y=1.25x+3.75
the equation to model data is
y=1.25x+3.75
see the attached figure
A (x1,y1)-------> (1,5)
B (x2,y2)------> (5,10)
C (x3,y3)------> (9,15)
D (x4,y4)------> (13,20)
find the slope
AB
m=(10-5)/(5-1)-----> m=5/4
find the slope
CB
m=(15-10)/(9-5)-----> m=5/4
find the slope
DC
m=(20-15)/(13-9)-----> m=5/4
so
<span>the relationship shown is linear
</span>
<span>to model the data with an equation find the equation of a line
</span>with m=5/4 and point A (1,5)
y-y1=m*(x-x1)-----> y-5=(5/4)*(x-1)----> y=1.25x-1.25+5-----> y=1.25x+3.75
the equation to model data is
y=1.25x+3.75
see the attached figure