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balandron [24]
3 years ago
8

What is a partition gap, and how might it be used to hide data?â?

Computers and Technology
2 answers:
o-na [289]3 years ago
4 0
Partition is a logical drive.  Large disks have to be partitioned in order to be structured. Knowing what partition is, partition gap refers to the unused space between partitions. It is also "Inter-partition<span> space" which</span><span> can be used to hide data on a hard disk. In this case a disk editor utility is used to access the hidden data in the partition gap.</span>
TEA [102]3 years ago
3 0

Answer:

Partition gap is a method in which to create different spaces within a disk so that it is as if there were actually more than one hard disk, something that you can use to store data or install other operating systems.

Explanation:

A partition is the name given to each division present in a single physical data storage unit. To be understood, having multiple partitions is like having several hard drives on a single physical hard drive, each with its file system and working differently.

Partitions can be used for several purposes. On the one hand, you can have one dedicated to saving sensitive data with security measures that do not interfere with the rest of the system, as well as backups, although you can also use it to install different operating systems. In some of them, such as those based on GNU / Linux, you can also structure the disk into partitions for the different types of files used by the operating system and even to hide information.

That is why one of the tasks performed by computer forensics is the investigation of hard disk partitions in search of hidden information.

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Dzięńdobry kto ogarnia komędy w minicraft bardzo dobrze i by mi pomógł w stworzeniu serwera [dostanie w zamian range właścieciel
mojhsa [17]

Playing Minecraft on a public server can take the game to a whole. This will help your kid learn social skills, such as cooperating, while there are some family-friendly servers for the Pocket Edition most server admins can “roll back” your building to the state it was in.

Explanation:

  • For Minecraft, you'll need to forward TCP port 25565 . You'll also need to enter your server's local IP address as the Output IP or Server IP for the forwarded port. This tells the router which device to point at. To find your server's local IP, open a command prompt and enter ipconfig.
  • They are safe for the most part, however they do expose you to the following risks, which can generally be negated by simply joining reputable servers. Some servers may ask users to set up an AuthMe password. If you decide to enter a password here, never ever enter the password of your Minecraft account.
  • You can divide public Minecraft servers into two types:
  1. Whitelisted servers are protected by a whitelist — that is, a list of usernames that are allowed to join the server. To join a whitelisted server, you need to apply to have your Minecraft username added to the whitelist. Typically, this involves filling out a form and waiting a few hours or days.
  2. Non-whitelisted servers do not have a whitelist, which means anyone can join the server simply by entering the server’s address in their Minecraft client, as shown above.
  • Applying for a whitelisted server can be a bit of a drag especially when you have an impatient eight-year-old tugging at your sleeve but it does provide an extra degree of reassurance that all the players on the server are known to the server administrators.
8 0
4 years ago
What are two benefits of consumer programs
Tcecarenko [31]

They help consumers identify the best product reviews from various sources.

They help prosecute companies that sell unsafe products to consumers.

5 0
4 years ago
Write a complete Java program called Rooter that gets a positive integer called "start" from the user at the command line and th
Nataly_w [17]

Answer:

The program in Java is as follows:

import java.util.*;

import java.lang.Math;

public class Rooter{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

 int start;

 System.out.print("Start: ");

 start = input.nextInt();

 while(start<=0){

     System.out.print("Number must be positive\nStart: ");

     start = input.nextInt();  }

 while(start>=0){

     System.out.println(Math.sqrt(start));

     start--;  }

}

}

Explanation:

This declares start as integer

 int start;

This prompts the user for input

 System.out.print("Start: ");

This gets input for start

 start = input.nextInt();

The following is repeated until the user input is valid i.e. positive

<em>  while(start<=0){</em>

<em>      System.out.print("Number must be positive\nStart: ");</em>

<em>      start = input.nextInt();  }</em>

The following while loop prints the square root of each number till 0

<em>  while(start>=0){</em>

<em>      System.out.println(Math.sqrt(start));</em>

<em>      start--;  }</em>

4 0
3 years ago
Linda is searching for a new job. Which information would her potential employers likely review in her social profile?
nasty-shy [4]
The answer will be A they would wanna know about her work history
3 0
3 years ago
Read 2 more answers
Consider sending a 2400-byte datagram into a link that has an mtu of 700 bytes. suppose the original datagram is stamped with th
Feliz [49]

Explanation:

Let, DG is the datagram so, DG= 2400.

Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.

Let, M is the MTU so, M=700.

Let, IP is the IP header so, IP= 20.

Let, id is the identification number so, id=422

Required numbers of the fragment = [\frac{DG-IP}{M-IP} ]

Insert values in the formula = [\frac{2400-20}{700-20} ]

Then,        = [\frac{2380}{680} ] = [3.5]

The generated numbers of the fragment is 4

  • If FV = 1 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=0 and F=1.
  • If FV = 2 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=85(85*8=680 bytes) and F=1.
  • If FV = 3 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=170(170*8=1360 bytes) and F=1.
  • If FV = 4 then, bytes in data field of DG= 2380-3(680) = 340 and id=422 and FO=255(255*8=2040 bytes) and F=0.

3 0
4 years ago
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