1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marina CMI [18]
4 years ago
10

Hi, please help.

Mathematics
1 answer:
Lera25 [3.4K]4 years ago
7 0
It’s a machine that works easy and simple..?.?
You might be interested in
Factor:<br> 4b2 - 12b + 9
Vikentia [17]

Answer:

  (2b-3)²

Step-by-step explanation:

The square of a binomial is ...

  (p - q)² = p² - 2pq + q²

The fact that the first and last terms are perfect squares suggests that you might want to look to see if the middle term matches this form. It does.

For p² = 4b², p=2b.

For q² = 9, q = 3.

Then 2pq = 2(2b)(3) = 12b.

So, the factoring is ...

  4b² -12b +9 = (2b -3)²

5 0
4 years ago
(−9+6.8−1.2)·(−0.49−0.51)
zmey [24]

Answer:

3.4

Step-by-step explanation:

(−9 + 6.8 − 1.2) · (−0.49 − 0.51)

(−3.4) · (−1)

3.4

6 0
3 years ago
Read 2 more answers
HELP 100 POINTS The population of a city is modeled with the function P=250,000e^0.013t​, where t is the number of years since 2
erma4kov [3.2K]
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
6 0
2 years ago
The sugar content of the syrup is canned peaches is normally distributed. Assumethe can is designed to have standard deviation 5
andreyandreev [35.5K]

Answer: 0.50477

Step-by-step explanation:

Given : The sugar content of the syrup is canned peaches is normally distributed.

We assume the can is designed to have standard deviation \sigma=5 milligrams.

The sampling distribution of the sample variance is chi-square distribution.

Also,The data yields a sample standard deviation of s=4.8 milligrams.

Sample size : n= 10

Test statistic for chi-square :\chi^2=\dfrac{s^2(n-1)}{\sigma^2}

i.e. \chi^2=\dfrac{(4.8)^2(10-1)}{(5)^2}=8.2944

Now, P-value = P(\chi^2>8.2944)=0.50477  [By using the chi-square distribution table for p-values.]

Hence, the chance of observing the sample standard deviation greater than 4.8 milligrams = 0.50477

8 0
3 years ago
Describe the relationship between x and why in a line with negative slope
bulgar [2K]

In a line with negative slope, as x increase, y decreases.

3 0
3 years ago
Other questions:
  • What is the circumference of the blue circle?
    7·1 answer
  • Macky drank 6 bottles of water over 8 tennis practices. How much water did Macky drink each practice if she drank the same amoun
    9·1 answer
  • Without solving what can you tell about the solution to this equation?<br> 0.002n + 15 =2
    13·2 answers
  • 10(x-5)+5x-6 solve using distributive property and simplify
    15·2 answers
  • PLZ HELP!! I’m really confused.
    9·2 answers
  • When 3x^2-12x-7 is written in the form of a (x-h)^2+k, what is the value of a,h, and k?
    14·1 answer
  • I SUCK IN THIS LESSON. PLEASE PLEASE HELP NO LINKS!
    13·1 answer
  • Hello can some one please answer this ASAP
    5·1 answer
  • Can yall help me do this
    14·2 answers
  • Determine the domain of (g ∘ f)(x) if f (x) = x2 + x − 3 and g of x is equal to 1 over the quantity x plus 1 end quantity period
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!