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3 years ago

Ratio equal to 90:18

Mathematics

1 answer:

Vadim26 [7]3 years ago

6 0

90:18

divide using 3 on both sides

90:18

30:6

10:2

now lets use 2

10:2

5:1

5:1 is the equal ratio to 90:18

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Question 10

EleoNora [17]

Answer:

a.(-b) ( third choice)

explanation:

-a+b - there is no plus sign for -a.b.

not -a+b

(-a)(-6)=6a (-negative sign and -negative sign=+positive sign)

5 0

3 years ago

Jenny paid $17 for 2 large boxes of popcorn and 3 large soft drinks. Justin paid $10 for 1 large box of popcorn and 2 large soft

wolverine [178]

2p + 3d = 17

1p + 2d = 10

D is the correct answer

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3 years ago

PLEASE HELP ME !<br> (2,7); 3x-y =5<br> show all steps !

Zigmanuir [339]

Answer:

i dont think you've got the right (x,y) pair....

Step-by-step explanation:

3x - y = 5

3(2) - 7 = 5

6 - 7 = 5

those are not the correct coordinates for the equation

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3 years ago

The frequency distributions of two data sets are shown in the dot plots below.

fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

$\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}$

$\text{Mean of data set 1}=\frac{45}{19}$

$\text{Mean of data set 1}=2.3684\approx 2.37$

$\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}$

$\text{Mean of data set 2}=\frac{38}{18}$

$\text{Mean of data set 2}=2.11$

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

$\text{Median of data set 2}=\frac{2+2}{2}$

$\text{Median of data set 2}=\frac{4}{2}=2$

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.

$Q_1\text{ of data set 1}=1$

$Q_3\text{ of data set 1}=3$

$\text{IQR of data set 1}=3-1=2$

$Q_1\text{ of data set 2}=1$

$Q_3\text{ of data set 2}=3$

$\text{IQR of data set 2}=3-1=2$

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0

3 years ago

Read 2 more answers

Sheila buys two concert tickets from her friend she pays $90 for the two tickets she looks at the tickets and sees that each tic

Maru [420]

Cost of two tickets that Sheila paid to her friend = $ 90

Actual price of 1 ticket = $ 52.50

So, actual price of 2 tickets = $52.50\times2=105$

Hence, markdown or discount Sheila's friend gave her is =

$105-90=15$

The answer is $15.

8 0

3 years ago

Read 2 more answers