All categories

3 years ago

Ratio equal to 90:18

Mathematics

1 answer:

Vadim26 [7]3 years ago

6 0

90:18

divide using 3 on both sides

90:18

30:6

10:2

now lets use 2

10:2

5:1

5:1 is the equal ratio to 90:18

You might be interested in

Molly earns $6 for each hour she babysits plus $10 to cover any personal

qwelly [4]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Dale made $105 for 7 hours of work. At the same rate, how much would he make for 9 hours of work? helppp please

Minchanka [31]

You would have to divide 105 by 7 and get an answer then you times that answer by nine and get your answer

5 0

3 years ago

Read 2 more answers

if you make $300 and you spend $237 and then you make $40 more and spend $60 how much money do you have left?

AleksandrR [38]

The answer would be $43.
Hope this helps:)

8 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago

Can u help sold this

solong [7]

Answer:

Step-by-step explanation:

To calculate the slope or gradient we use this formula:

Slope = y2-y1/x2-x1

(-3,2) = (x1, y1)

(4,2) = (x2, y2)

Slope = 2-2/4-(-3) = 0

Answer from Gauthmath

4 0

3 years ago