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Elena L [17]
3 years ago
5

A boy walked to the store with 3 apples. He dropped two of them. How many does he have left. PLEASE HELP

Mathematics
1 answer:
Illusion [34]3 years ago
7 0

Answer:

Doesnt he still have 3? All he did was drop 2

Step-by-step explanation:

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Which of the following has a unit price (price per item) of $0.25? Choose 2. *
exis [7]

Answer:

8 pieces/$2.00

6 pieces/$1.50

Step-by-step explanation:

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Dawn has 2 quarters, 1 nickel,<br> and one $1 bill. How much<br> money does Dawn have?
Anna007 [38]

Answer:

$1.55

Step-by-step explanation:

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The daily advertising revenue (in dollars) for a local newspaper is given by the function R(t) = -18t2 + 720t – 103, where t is
erastovalidia [21]

Answer:

6647

Step-by-step explanation:

The computation of the advertising revenue for 15 years is shown below:

Given that

r(t) = -18t^2 + 720t - 103

where

t = number of years = 15

now put the value of t in the above equation

= -18(15)^2 + 720(15) - 103

= -4050 + 10,800 - 103

= 6647

6 0
3 years ago
A ball is kicked upward with an initial velocity of 56 feet per second. The ball's height h (in feet) can be expressed as a func
siniylev [52]

Answer:

1.75

Step-by-step explanation:

h(t) = -16t² + 56t

h'(t) = -32t + 56

To find time at max height equate h' to 0

0 = -32t + 56

t = 56/32 = 1.75 s

It takes 1.75 s to reach max highest point

8 0
3 years ago
If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?
Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

m\angle B=\sin ^{-1}(\dfrac{m}{n})

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times h

Where, b is the base and h is the height of the triangle.

Area=\dfrac{1}{2}\times a\times h

The area of the triangle ABC is D.

D=\dfrac{1}{2}\times a\times h

2D=ah

\dfrac{2D}{a}=h                  ...(i)

In a right angle triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin B =\dfrac{h}{c}

\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}              [Using (i)]

\sin B =\dfrac{2D}{ac}

m\angle B =\sin ^{-1}\dfrac{2D}{ac}            ...(ii)

We have,

m\angle B=\sin ^{-1}(\dfrac{m}{n})          ...(iii)

On comparing (ii) and (iii), we get

m=2D

n=ac

Therefore, the required values are m=2D, n=ac.

6 0
3 years ago
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