Answer:
f(x) = -(x-3)^2 + 4
Step-by-step explanation:
(h; k) are the coordinates of the vertex.
On the graph are (3, 4), therefore we have:
f(x) = a(x-3)^2 + 4
We have the x- intercept (1,0) -> x=1; y=0.
Substitute them into the equation:
0 = a(1 - 3)^2 + 4
0 = a(-2)^2 + 4
4a + 4 = 0 | -4
4a = -4 |-4
a = -1
So, we have the answer:
f(x) = -(x-3)^2 + 4
Answer:
(0, -5), (4, -2), (-16, -17)
Step-by-step explanation:
I attach your full question in the image below
The equation is
3x-4y-8=12
Which can be rewritten as
3x-4y =12 +8
3x-20 = 4y
y = (3/4)*x - 5
We need to check each individual case
(0,-5)
y = (3/4)*(0) - 5
y = -5
True
(4,-2)
y = (3/4)*(4) - 5
y = -2
True
(8,2)
y = (3/4)*(8) - 5
y = 1
False
(-16,-17)
y = (3/4)*(-16) - 5
y = -17
True
(-1,-8)
y = (3/4)*(-1) - 5
y = -23/4
False
(-40,-34)
y = (3/4)*(-40) - 5
y = -35
False
(0,-5) (4,-2) and (-16,-17) are the solutions
5,500 days or what? I don't get it
All you have to do is plug it into slope-intercept form, which is y = mx + b
y = (-2)x + 4
y = -2x + 4
the answer is A