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Rom4ik [11]
2 years ago
11

5/30 as a decimal25/30 as a decimal

Mathematics
2 answers:
Sonbull [250]2 years ago
8 0

Answer:


Step-by-step explanation:

5/30 as a decical is 0.166 repeating (0.167 rounded)

25/30 as a decimal is 0.833 repeating (0.833 rounded)

Anastaziya [24]2 years ago
7 0

Answer:

5/30: 0.166~

25/30: 0.833~

Step-by-step explanation:

Divide 5 by 30, and 25 by 30

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Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap
11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=20$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

5 0
3 years ago
What is the equation of a line with a slope of -1 and a y-intercept of -5​
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Answer:

-x-5

Step-by-step explanation:

Not even going to explain this

8 0
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Two sisters drove 144 miles on a camping trip. They averaged at least 32 miles per gallon on the trip. Describe the number of ga
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<span>The answer should be 4.5 because they used AT LEAST 32 miles per gallon. So, 144/32=4.5 and since it's AT LEAST 32, 4.5 is the max amount used.</span>
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3 years ago
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How do I factor x^4-5x^2+6?
Vilka [71]

Answer:

=(x^2-3)(x^2-2)

Step-by-step explanation:

So we have the expression:

x^4-5x^2+6

And we wish to factor it.

First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

=u^2-5u+6

This is a technique called quadratic u-substitution. Now, we can factor in this form.

We can use the numbers -3 and -2. So:

=u^2-2u-3u+6

For the first two terms, factor out a u.

For the last two terms, factor out a -3. So:

=u(u-2)-3(u-2)

Grouping:

=(u-3)(u-2)

Now, substitute back the x² for u:

=(x^2-3)(x^2-2)

And this is the simplest form.

And we're done!

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The value of “u” is 32°.
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