4 is the correct answer i believe! :) sorry if wrong.
please put brainliest!
Answer:
m = 3, n = -2.
Step-by-step explanation:
Substitute n = 3m - 11 in the second equation:
2m + 3(3m - 11) = 0
2m + 9m - 33 = 0
11m = 33
m = 3.
Substitute for m in n = 3m-11:
n = 3(3) - 11
n = -2.
Answer:
![[ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}](https://tex.z-dn.net/?f=%5Bln%20%5Cfrac%7Bx%28x%5E2%20%2B%201%29%7D%7B%28x%20%2B%201%29%7D%5D%5E%5Cfrac%7B3%7D%7B2%7D)
Step-by-step explanation:
![\frac{3}{2} [ln x(x^2 + 1) - ln(x + 1)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%20%5Bln%20x%28x%5E2%20%2B%201%29%20-%20ln%28x%20%2B%201%29%5D)
ln(m/n)= lnm - ln(n)
![\frac{3}{2}[ln x(x^2 + 1) - ln(x + 1)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bln%20x%28x%5E2%20%2B%201%29%20-%20ln%28x%20%2B%201%29%5D)
![\frac{3}{2}[ln \frac{x(x^2 + 1)}{(x + 1)}]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bln%20%5Cfrac%7Bx%28x%5E2%20%2B%201%29%7D%7B%28x%20%2B%201%29%7D%5D)
3/2 is before ln. so we move the fraction 3/2 to the exponent
as per log property we move the fraction to the exponent
![[ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}](https://tex.z-dn.net/?f=%5Bln%20%5Cfrac%7Bx%28x%5E2%20%2B%201%29%7D%7B%28x%20%2B%201%29%7D%5D%5E%5Cfrac%7B3%7D%7B2%7D)
9514 1404 393
Answer:
x = -1, 1, 9
Step-by-step explanation:
You want x such that f(x) = g(x). Subtracting g(x) from both sides of this equation lets us rewrite it as ...
f(x) -g(x) = 0
x³ -9x² -(x -9) = 0
x²(x -9) -1(x -9) = 0 . . . factor the first pair of terms
(x² -1)(x -9) = 0 . . . . . . use the distributive property
(x -1)(x +1)(x -9) = 0 . . . . factor the difference of squares
Values of x that make these factors zero will make f(x) = g(x):
x = -1, 1, 9 for f(x) = g(x)
18/24 divde both by 6 to get simplest form
3/4