Answer:(a)x^2+2y^2=2
(b)In the attached diagram
Step-by-step explanation:Step 1: Multiply both equations by t
xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)
Step 1: Multiply both equations by t
xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)
Step 2:We square both equations
(xt)^2=t^2(cost -sint)^2\\(ty)^2(\sqrt{2})^2 =t^2(cost +sint)^2
Step 3: Adding the two equations
(xt)^2+(ty)^2(\sqrt{2})^2=t^2(cost -sint)^2+t^2(cost +sint)^2\\t^2(x^2+2y^2)=t^2((cost -sint)^2+(cost +sint)^2)\\x^2+2y^2=(cost -sint)^2+(cost +sint)^2\\(cost -sint)^2+(cost +sint)^2=2\\x^2+2y^2=2 hopes this helps
Ok...I considered it....oh..u want me to answer it...lol..ok
5/6(1/2x + 6) - 3x
5/12x + 30/6 - 3x
5/12x - 36/12x + 5
- 31/12x + 5 <===
5x+14
You will collect the like terms
Answer:
Step-by-step explanation:
since -1≤sin2x≤1 no x values would satisfy the equation
Answer:
Answer is 80.36
Step-by-step explanation:
V=πr2h=π·2.12·5.8≈80.35566
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