H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.
<h3>How to Interpret Machine Language?</h3>
A language is referred to as Decidable or Recursive if there is a Turing machine that accepts and halts on every input string w. This tells us that every decidable language is Turing-Acceptable.
Now, we are told that the halting language is reducible to some language B. This means that it is an undecidability via reduction.
Now, Using the idea that “ If A is undecidable and reducible to B, then B is undecidable.” Suppose R decides HALT_TM, we will construct S to decide ATM .
S = “On input (M, B)
This means that H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.
Read more about machine language at; brainly.com/question/28026656
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D. since 11% in decimal is 0.11 only. 1/9 in decimal is 0.111111111... 0.12 jorge and 1/8 in decimal is 0.125
The median would decrease because the temperature given is lower than the median
Triangle area = 8 x 3/2
= 12
12 x 2 = 24cm^2 for 2 triangles
Height of rectangle must be found, so use pythag on triangle
a^2+ b^2 = c^2
16 + 9 =c^2
C=5
A= 5 x 12
= 60
60 x 3 triangles in total is 180cm^2
180cm^2 + 24cm^2 = 204cm^2
Ans: 204cm^2
Ouuuu I don’t that sorry but yeah
