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2 years ago

What is 8x to the power 3 over 6x to the power 5

Mathematics

1 answer:

bulgar [2K]2 years ago

3 0

In this question, you're simplifying the "fraction".

Simplify:

8x² / 6x^5

First, simplify the 8 and the 6 by dividing by 2

4x² / 3x^5

Now simplify the exponents:

The exponents is equivalent to: x² - x^5

x² - x^5 = -x²

Since it's a negative, it would stay in the bottom of the fraction, or the denominator.

4 / 3x²

Answer:

4 / 3x²

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Evaluate 2b + c for b = 5 and c = 5 Please help

Svet_ta [14]

Answer:

2(5)+5=15

Step-by-step explanation:

1. you have the equation 2b+c

2. then you add the numbers for c and b

3. so b=5 and c=5

4. once you add it into the problem then you get 2(5)+5 make sure you remember to times 2 x 5

5. then you do PEMDAS

6. you do multiply so 2x5 is 10

7. then do 10+5 and you get 15 as your answer.

7 0

3 years ago

Please someone answer this, “what is the area of triangle ABC?”

prisoha [69]

Here's the solution,

The given triangle is an equilateral triangle, because it's all angles measure 60° each

now,

Area of an equilateral triangle :

=》

$\dfrac{ \sqrt{3} }{4} {a}^{2}$

where,

a = 8 ( side measure )

=》

$\dfrac{ \sqrt{3} }{4} \times 8 \times 8$

=》

$\sqrt{3} \times 16$

=》

$16 \sqrt{3} \: \: \: cm {}^{2}$

=》

$27.71 \: \: cm {}^{2}$

4 0

3 years ago

True or false: the equation tan^2x+1=sec^2x

zhenek [66]

ANSWER

True

EXPLANATION

The given trigonometric equation is:

${ \tan}^{2} x + 1 = { \sec}^{2} x$

We take the LHS and simplify to arrive at the RHS.

${ \tan}^{2} x + 1 = \frac{{ \sin}^{2} x}{{ \cos}^{2} x} + 1$

Collect LCM on the right hand side to get;

${ \tan}^{2} x + 1 = \frac{{ \sin}^{2} x + {\cos}^{2} x}{{ \cos}^{2} x}$

This implies that

${ \tan}^{2} x + 1 = \frac{1}{{ \cos}^{2} x} .$

${ \tan}^{2} x + 1 = {( \frac{1}{ \cos(x) }) }^{2}$

${ \tan}^{2} x + 1 = { \sec}^{2} x$

This identity has been verified .Therefore the correct answer is true.

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2 years ago

(7x2+3x-6)-(-4x2+x-2)

Alex17521 [72]

The correct answer is 4 ( 6x - 1 )

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3 years ago

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Count by ones from 368 to 500

Marta_Voda [28]

Um.... 368 369 370 371 372 372 374 375 376 377 378 379 etc

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3 years ago

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