I think that they all died of a natural disaster, such as a hurricane or flood since they were very close to the water.
Answer:
Brittle materials:
Brittle materials are those material which does not shows any indication before failure.It means that they break suddenly without showing any indication.These materials have zero ductility.
Ex :
1.Glass is the very common example for brittle material and in our house we can easily see that when ever glass fall on the floor it breaks in very small pieces.
2. Metal objects are made from metal they behave as brittle like cast iron.
3. The another familiar example in our house for brittle material is dry clay.
Ductile materials:
Ductile materials which shows a indication before fracture.It have a range ,within this range they did not fail.The ability of material to draw into wires is known as ductility of that materials.
Ex :Those object are made from carbon steel,gold,silver etc.
Elastic deformation :
To regain the original shape after removal of load is known as elastic deformation.
Ex: The familiar example of elastic deformation is rubber band ,when we apply a force on the rubber band then it goes under the deformation but after removal the load come back on the original position.
Answer and Explanation:
The offshore or coastal or littoral regions have very rare experience of extreme variations in temperature, this is due to the fact that the heat capacity of water is higher than it is on the land which means that it takes longer time for water to vary its temperature i.e., it takes longer time for water to get heated or be cooled. Therefore, it goes with the established fact of heat capacity of water that the regions far away from the ocean or littoral regions experience extreme temperature variations as compared to the areas closer to the coastal regions and these areas have moderate temperature i.e., neither too hot in summers nor cold in winters.
The answer would be false
Answer:
transmissivity =0.0001458235 m² / year
Explanation:
given data
discharge = 6,000 acre - feet/year = 0.001775566 cubic miles
width of aquifer = 1.8 miles
Gradient = 0.95%
to find out
what would be the average transmissivity of the aquifer
solution
we know that transmissivity formula that is
transmissivity = 
here Q is discharge and W is width and i is gradient
so put here value
transmissivity =
transmissivity = 
transmissivity =0.0010383427 mile² / year
and we know 1 miles² = 2589988.11 m²
so
transmissivity =0.0001458235 m² / year
